3=(x+4)^2-y

Lösung

3 = (x + 4)^{2} - y

(h, k) = (- 4, - 3), p = \frac{1}{4}

Schritte zur Lösung

3 = (x + 4)^{2} - y

Rewrite

3 = (x + 4)^{2} - y

in the standard form:

4 \cdot \frac{1}{4} (y - (- 3)) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 3), p = \frac{1}{4}