(y+3)^2=4(x+1)

Lösung

(y + 3)^{2} = 4 (x + 1)

(h, k) = (- 1, - 3), p = 1

Schritte zur Lösung

(y + 3)^{2} = 4 (x + 1)

Rewrite

(y + 3)^{2} = 4 (x + 1)

in the standard form:

4 \cdot 1 \cdot (x - (- 1)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 3), p = 1

(y - 1)^{2} = 2 (x + 1)

y^{2} + x - 4 = 0

x^{2} = 64 (y - 5)

x^{2} - 20 y = 0

y^{2} = x + 36