exzentrizität 10x^2+5y^2=50

Lösung

exzentrizität

10 x^{2} + 5 y^{2} = 50

\frac{1}{2}

Dezimale

0.70710 \dots

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

10 x^{2} + 5 y^{2} = 50 :

Ellipse with center

(h, k) = (0, 0), b = 10, a = 5

= \frac{( 10 ) ^{2} - ( 5 ) ^{2}}{10}

\frac{( 10 ) ^{2} - ( 5 ) ^{2}}{10} = \frac{1}{2}

= \frac{1}{2}

ecce n t r i c i t y \frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

ecce n t r i c i t y 4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

ecce n t r i c i t y 4 x^{2} + 3 y^{2} - 8 x + 18 y + 19 = 0

ecce n t r i c i t y \frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

ecce n t r i c i t y 36 x^{2} + 9 y^{2} + 36 y - 288 = 0