exzentrizität (x^2)/(16)+(y^2)/(25)=1

Lösung

exzentrizität

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

\frac{3}{5}

Dezimale

0.6

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 4

= \frac{5 ^{2} - 4 ^{2}}{5}

\frac{5 ^{2} - 4 ^{2}}{5} = \frac{3}{5}

= \frac{3}{5}

ecce n t r i c i t y 18 y^{2} + 24 y + 12 x^{2} - 12 x = 1

ecce n t r i c i t y 9 x^{2} + 4 y^{2} + 54 x - 8 y + 49 = 0

ecce n t r i c i t y (\frac{x}{8})^{2} + (\frac{y}{6})^{2} = 1

ecce n t r i c i t y 4 x^{2} + 9 y^{2} - 8 x - 32 = 0

ecce n t r i c i t y 9 x^{2} + 6 y^{2} = 54