de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

y^2<= x^2+y

Lösung

y^{2} \leq x^{2} + y

Lösung

(h, k) = (0, \frac{1}{2}), a = \frac{1}{2}, b = \frac{1}{2}

Schritte zur Lösung

y^{2} \leq x^{2} + y

Rewrite

y^{2} \leq x^{2} + y

in the form of a standard hyperbola equation

\frac{( y - \frac{1}{2} ) ^{2}}{( \frac{1}{2} ) ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, \frac{1}{2}), a = \frac{1}{2}, b = \frac{1}{2}

Graph

Beliebte Beispiele

36 y^{2} = 4 x^{2} + 144

y^{2} - 9 = x^{2}

3y^2-12x^2-36y-48x+48=0

3 y^{2} - 12 x^{2} - 36 y - 48 x + 48 = 0

((y+7)^2)/4-((x+2)^2)/(16)=1

\frac{( y + 7 ) ^{2}}{4} - \frac{( x + 2 ) ^{2}}{16} = 1

((x-5)^2)/4-((y+2)^2)/9 =1

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1