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Beliebt Geometry >

3y^2+4x+4y-14=0

Lösung

3 y^{2} + 4 x + 4 y - 14 = 0

Lösung

(h, k) = (\frac{23}{6}, - \frac{2}{3}), p = - \frac{1}{3}

Schritte zur Lösung

3 y^{2} + 4 x + 4 y - 14 = 0

Rewrite

3 y^{2} + 4 x + 4 y - 14 = 0

in the standard form

4 (- \frac{1}{3}) (x - \frac{23}{6}) = (y - (- \frac{2}{3}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{23}{6}, - \frac{2}{3}), p = - \frac{1}{3}

Graph

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