x=2(y+1)^2-2

Lösung

x = 2 (y + 1)^{2} - 2

(h, k) = (- 2, - 1), p = \frac{1}{8}

Schritte zur Lösung

x = 2 (y + 1)^{2} - 2

Rewrite

x = 2 (y + 1)^{2} - 2

in the standard form:

4 \cdot \frac{1}{8} (x - (- 2)) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 1), p = \frac{1}{8}

y > (x - 5) (x + 1)

y = - x^{2} - 2 x + 24

0 = 3 y^{2} + x - 1

(x - 3)^{2} = 4 (y - 1)

y^{2} - 12 x - 16 y + 4 = 0