cos(t)=-(sqrt(3))/2

Lösung

cos (t) = - \frac{3}{2}

t = \frac{5 π}{6} + 2 πn, t = \frac{7 π}{6} + 2 πn

Grad

t = 15 0^{\circ} + 36 0^{\circ} n, t = 21 0^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (t) = - \frac{3}{2}

Allgemeine Lösung für

cos (t) = - \frac{3}{2}

cos (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{5 π}{6} + 2 πn, t = \frac{7 π}{6} + 2 πn

t = \frac{5 π}{6} + 2 πn, t = \frac{7 π}{6} + 2 πn

- 7 sin (7 x) = 0

5 cos (x) + 3 = - cos (x)

9 tan (x) sin (x) = - 5 sin (x)

cos (2 x) = 0, 0 \leq x \leq 2 π

cot^{2} (θ) - csc (θ) = 1