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人気のある三角関数 >

(sin(160))/5 =(sin(c))/4

解

\frac{sin ( 16 0 ^{\circ} )}{5} = \frac{sin ( c )}{4}

解

c = 0.27715 \dots + 36 0^{\circ} n, c = 18 0^{\circ} - 0.27715 \dots + 36 0^{\circ} n

+1

ラジアン

c = 0.27715 \dots + 2 πn, c = π - 0.27715 \dots + 2 πn

解答ステップ

\frac{sin ( 16 0 ^{\circ} )}{5} = \frac{sin ( c )}{4}

辺を交換する

\frac{sin ( c )}{4} = \frac{sin ( 16 0 ^{\circ} )}{5}

以下で両辺を乗じる:

4

\frac{sin ( c )}{4} = \frac{sin ( 16 0 ^{\circ} )}{5}

以下で両辺を乗じる:

4

\frac{4 sin ( c )}{4} = \frac{4 sin ( 16 0 ^{\circ} )}{5}

簡素化

sin (c) = \frac{4 sin ( 16 0 ^{\circ} )}{5}

sin (c) = \frac{4 sin ( 16 0 ^{\circ} )}{5}

三角関数の逆数プロパティを適用する

sin (c) = \frac{4 sin ( 16 0 ^{\circ} )}{5}

以下の一般解

sin (c) = \frac{4 sin ( 16 0 ^{\circ} )}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

c = arcsin (\frac{4 sin ( 16 0 ^{\circ} )}{5}) + 36 0^{\circ} n, c = 18 0^{\circ} - arcsin (\frac{4 sin ( 16 0 ^{\circ} )}{5}) + 36 0^{\circ} n

c = arcsin (\frac{4 sin ( 16 0 ^{\circ} )}{5}) + 36 0^{\circ} n, c = 18 0^{\circ} - arcsin (\frac{4 sin ( 16 0 ^{\circ} )}{5}) + 36 0^{\circ} n

10進法形式で解を証明する

c = 0.27715 \dots + 36 0^{\circ} n, c = 18 0^{\circ} - 0.27715 \dots + 36 0^{\circ} n

グラフ

人気の例

sin(x)+sqrt(2)=0

sin (x) + 2 = 0

sin (θ) = - \frac{24}{25}

cos(2x)+7sin(x)-4=0

cos (2 x) + 7 sin (x) - 4 = 0

tan(θ/8)+sqrt(3)=0

tan (\frac{θ}{8}) + 3 = 0

sin(θ/2)-1=0,0<= θ<= 2pi

sin (\frac{θ}{2}) - 1 = 0, 0 \leq θ \leq 2 π