zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

5csc(θ)+6=0

解答

5 csc (θ) + 6 = 0

解答

θ = - 0.98511 \dots + 2 πn, θ = π + 0.98511 \dots + 2 πn

+1

度数

θ = - 56.44269 \dots^{\circ} + 36 0^{\circ} n, θ = 236.44269 \dots^{\circ} + 36 0^{\circ} n

求解步骤

5 csc (θ) + 6 = 0

将

6

到右边

5 csc (θ) + 6 = 0

两边减去

6

5 csc (θ) + 6 - 6 = 0 - 6

化简

5 csc (θ) = - 6

5 csc (θ) = - 6

两边除以

5

5 csc (θ) = - 6

两边除以

5

\frac{5 csc ( θ )}{5} = \frac{- 6}{5}

化简

csc (θ) = - \frac{6}{5}

csc (θ) = - \frac{6}{5}

使用反三角函数性质

csc (θ) = - \frac{6}{5}

csc (θ) = - \frac{6}{5}

的通解

csc (x) = - a \Rightarrow x = arccsc (- a) + 2 πn, x = π + arccsc (a) + 2 πn

θ = arccsc (- \frac{6}{5}) + 2 πn, θ = π + arccsc (\frac{6}{5}) + 2 πn

θ = arccsc (- \frac{6}{5}) + 2 πn, θ = π + arccsc (\frac{6}{5}) + 2 πn

以小数形式表示解

θ = - 0.98511 \dots + 2 πn, θ = π + 0.98511 \dots + 2 πn

作图

流行的例子

sin (x^{2}) = 1

cos(2θ)-sqrt(3)cos(θ)=0,0<= θ<2pi

cos (2 θ) - 3 cos (θ) = 0, 0 \leq θ < 2 π

2cos^2(θ)-7cos(θ)-4=0

2 cos^{2} (θ) - 7 cos (θ) - 4 = 0

sin(θ)= 3/10 ,sin(θ+pi/6)

sin (θ) = \frac{3}{10}, sin (θ + \frac{π}{6})

3sin^2(x)=8cos(x)

3 sin^{2} (x) = 8 cos (x)