cos(θ)= 6/10

Lösung

cos (θ) = \frac{6}{10}

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

Grad

θ = 53.13010 \dots^{\circ} + 36 0^{\circ} n, θ = 306.86989 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{6}{10}

Streiche die gemeinsamen Faktoren:

2

cos (θ) = \frac{3}{5}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{3}{5}

Allgemeine Lösung für

cos (θ) = \frac{3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

- 5 sin^{2} (x) - 4 cos (x) = - 4

tan^{2} (θ) = \frac{1}{3}, 0 \leq θ \leq 2 π

4 sin (2 x) = 23

3 cos (2 θ) - 5 cos (θ) - 1 = 0

csc (x) = \frac{21}{5}