cos(θ)= 9/41

Lösung

cos (θ) = \frac{9}{41}

θ = 1.34948 \dots + 2 πn, θ = 2 π - 1.34948 \dots + 2 πn

Grad

θ = 77.31961 \dots^{\circ} + 36 0^{\circ} n, θ = 282.68038 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{9}{41}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{9}{41}

Allgemeine Lösung für

cos (θ) = \frac{9}{41}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{9}{41}) + 2 πn, θ = 2 π - arccos (\frac{9}{41}) + 2 πn

θ = arccos (\frac{9}{41}) + 2 πn, θ = 2 π - arccos (\frac{9}{41}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 1.34948 \dots + 2 πn, θ = 2 π - 1.34948 \dots + 2 πn

cos (x) = \frac{13}{19}

0 = 3 cos (2 x)

sin^{2} (x) - 9 cos (x) + 9 = 0

cos (x) = \frac{13}{16}

tan^{2} (x) - 4 tan (x) + 3 = 0