zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

sin(arctan(-1)+arcsin(-(sqrt(2))/2))

解答

sin (arctan (- 1) + arcsin (- \frac{2}{2}))

解答

- 1

求解步骤

sin (arctan (- 1) + arcsin (- \frac{2}{2}))

使用三角恒等式改写:

- sin (arctan (1)) cos (arcsin (\frac{2}{2})) - cos (arctan (1)) sin (arcsin (\frac{2}{2}))

sin (arctan (- 1) + arcsin (- \frac{2}{2}))

使用角和恒等式:

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

= sin (arctan (- 1)) cos (arcsin (- \frac{2}{2})) + cos (arctan (- 1)) sin (arcsin (- \frac{2}{2}))

利用以下特性:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{2}{2}) = - arcsin (\frac{2}{2})

= sin (arctan (- 1)) cos (arcsin (- \frac{2}{2})) + cos (arctan (- 1)) sin (- arcsin (\frac{2}{2}))

利用以下特性:

sin (- x) = - sin (x)

sin (- arcsin (\frac{2}{2})) = - sin (arcsin (\frac{2}{2}))

= sin (arctan (- 1)) cos (arcsin (- \frac{2}{2})) + cos (arctan (- 1)) (- sin (arcsin (\frac{2}{2})))

利用以下特性:

arctan (- x) = - arctan (x)

arctan (- 1) = - arctan (1)

= sin (arctan (- 1)) cos (arcsin (- \frac{2}{2})) + cos (- arctan (1)) (- sin (arcsin (\frac{2}{2})))

利用以下特性:

cos (- x) = cos (x)

cos (- arctan (1)) = cos (arctan (1))

= sin (arctan (- 1)) cos (arcsin (- \frac{2}{2})) + cos (arctan (1)) (- sin (arcsin (\frac{2}{2})))

利用以下特性:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{2}{2}) = - arcsin (\frac{2}{2})

= sin (arctan (- 1)) cos (- arcsin (\frac{2}{2})) + cos (arctan (1)) (- sin (arcsin (\frac{2}{2})))

利用以下特性:

cos (- x) = cos (x)

cos (- arcsin (\frac{2}{2})) = cos (arcsin (\frac{2}{2}))

= sin (arctan (- 1)) cos (arcsin (\frac{2}{2})) + cos (arctan (1)) (- sin (arcsin (\frac{2}{2})))

利用以下特性:

arctan (- x) = - arctan (x)

arctan (- 1) = - arctan (1)

= sin (- arctan (1)) cos (arcsin (\frac{2}{2})) + cos (arctan (1)) (- sin (arcsin (\frac{2}{2})))

利用以下特性:

sin (- x) = - sin (x)

sin (- arctan (1)) = - sin (arctan (1))

= (- sin (arctan (1))) cos (arcsin (\frac{2}{2})) + cos (arctan (1)) (- sin (arcsin (\frac{2}{2})))

化简

= - sin (arctan (1)) cos (arcsin (\frac{2}{2})) - cos (arctan (1)) sin (arcsin (\frac{2}{2}))

= - sin (arctan (1)) cos (arcsin (\frac{2}{2})) - cos (arctan (1)) sin (arcsin (\frac{2}{2}))

使用三角恒等式改写:

sin (arctan (1)) = \frac{2}{2}

sin (arctan (1))

使用三角恒等式改写:

sin (arctan (1)) = \frac{1 \cdot 1 + 1 ^{2}}{1 + 1 ^{2}}

利用以下特性:

sin (arctan (x)) = \frac{x 1 + x ^{2}}{1 + x ^{2}}

= \frac{1 \cdot 1 + 1 ^{2}}{1 + 1 ^{2}}

= \frac{1 \cdot 1 + 1 ^{2}}{1 + 1 ^{2}}

化简

= \frac{2}{2}

使用三角恒等式改写:

cos (arcsin (\frac{2}{2})) = \frac{1}{2}

cos (arcsin (\frac{2}{2}))

使用三角恒等式改写:

cos (arcsin (\frac{2}{2})) = 1 - (\frac{2}{2})^{2}

利用以下特性:

cos (arcsin (x)) = 1 - x^{2}

= 1 - (\frac{2}{2})^{2}

= 1 - (\frac{2}{2})^{2}

化简

= \frac{1}{2}

使用三角恒等式改写:

cos (arctan (1)) = \frac{2}{2}

cos (arctan (1))

使用三角恒等式改写:

cos (arctan (1)) = \frac{1 + 1 ^{2}}{1 + 1 ^{2}}

利用以下特性:

cos (arctan (x)) = \frac{1 + x ^{2}}{1 + x ^{2}}

= \frac{1 + 1 ^{2}}{1 + 1 ^{2}}

= \frac{1 + 1 ^{2}}{1 + 1 ^{2}}

化简

= \frac{2}{2}

使用三角恒等式改写:

sin (arcsin (\frac{2}{2})) = \frac{2}{2}

利用以下特性:

sin (arcsin (x)) = x

= \frac{2}{2}

= - \frac{2}{2} \frac{1}{2} - \frac{2}{2} \cdot \frac{2}{2}

化简

- \frac{2}{2} \frac{1}{2} - \frac{2}{2} \cdot \frac{2}{2} : - 1

- \frac{2}{2} \frac{1}{2} - \frac{2}{2} \cdot \frac{2}{2}

\frac{2}{2} \frac{1}{2} = \frac{1}{2}

\frac{2}{2} \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \frac{1}{2}}{2}

\frac{1}{2} = \frac{1}{2}

\frac{1}{2}

使用根式运算法则:

n \frac{a}{b} = \frac{n a}{n b},

假定

a \geq 0, b \geq 0

= \frac{1}{2}

使用法则

1 = 1

= \frac{1}{2}

= \frac{2 \frac{1}{2}}{2}

乘

2 \frac{1}{2} : 1

2 \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

约分:

2

= 1

= \frac{1}{2}

\frac{2}{2} \cdot \frac{2}{2} = \frac{1}{2}

\frac{2}{2} \cdot \frac{2}{2}

分式相乘:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 2}{2 \cdot 2}

22 = 2

22

使用根式运算法则:

a a = a

22 = 2

= 2

= \frac{2}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{2}{4}

约分:

2

= \frac{1}{2}

= - \frac{1}{2} - \frac{1}{2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 - 1}{2}

数字相减:

- 1 - 1 = - 2

= \frac{- 2}{2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{2}

使用法则

\frac{a}{a} = 1

= - 1

= - 1

流行的例子

tan((-1590)/(3cot^2(60)))

tan (\frac{- 159 0 ^{\circ}}{3 cot ^{2} ( 6 0 ^{\circ} )})

cos (46 5^{\circ})

arccos(sin((5pi)/2))

arccos (sin (\frac{5 π}{2}))

sin((7pi)/8)-sin((7pi)/6)-cot(pi/3)

sin (\frac{7 π}{8}) - sin (\frac{7 π}{6}) - cot (\frac{π}{3})

2sin(60)sec(30)cos(45)tan(45)

2 sin (6 0^{\circ}) sec (3 0^{\circ}) cos (4 5^{\circ}) tan (4 5^{\circ})