解答
csc(x)−sin(x)=cos(x)cot(3x−50)
解答
x=2π+2πn,x=23π+2πn,x=πn+25,x=2π+25+πn
+1
度数
x=90∘+360∘n,x=270∘+360∘n,x=1432.39448…∘+180∘n,x=1522.39448…∘+180∘n求解步骤
csc(x)−sin(x)=cos(x)cot(3x−50)
两边减去 cos(x)cot(3x−50)csc(x)−sin(x)−cos(x)cot(3x−50)=0
用 sin, cos 表示
csc(x)−sin(x)−cos(x)cot(−50+3x)
使用基本三角恒等式: csc(x)=sin(x)1=sin(x)1−sin(x)−cos(x)cot(−50+3x)
使用基本三角恒等式: cot(x)=sin(x)cos(x)=sin(x)1−sin(x)−cos(x)sin(−50+3x)cos(−50+3x)
化简 sin(x)1−sin(x)−cos(x)sin(−50+3x)cos(−50+3x):sin(x)sin(3x−50)sin(3x−50)−sin2(x)sin(3x−50)−cos(−50+3x)cos(x)sin(x)
sin(x)1−sin(x)−cos(x)sin(−50+3x)cos(−50+3x)
乘 cos(x)sin(−50+3x)cos(−50+3x):sin(−50+3x)cos(3x−50)cos(x)
cos(x)sin(−50+3x)cos(−50+3x)
分式相乘: a⋅cb=ca⋅b=sin(−50+3x)cos(−50+3x)cos(x)
=sin(x)1−sin(x)−sin(3x−50)cos(3x−50)cos(x)
将项转换为分式: sin(x)=1sin(x)=sin(x)1−1sin(x)−sin(−50+3x)cos(−50+3x)cos(x)
sin(x),1,sin(−50+3x)的最小公倍数:sin(x)sin(3x−50)
sin(x),1,sin(−50+3x)
最小公倍数 (LCM)
计算出由至少在以下一个因式表达式中出现的因子组成的表达式=sin(x)sin(3x−50)
根据最小公倍数调整分式
将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值 sin(x)sin(3x−50)
对于 sin(x)1:将分母和分子乘以 sin(3x−50)sin(x)1=sin(x)sin(3x−50)1⋅sin(3x−50)=sin(x)sin(3x−50)sin(3x−50)
对于 1sin(x):将分母和分子乘以 sin(x)sin(3x−50)1sin(x)=1⋅sin(x)sin(3x−50)sin(x)sin(x)sin(3x−50)=sin(x)sin(3x−50)sin2(x)sin(3x−50)
对于 sin(−50+3x)cos(−50+3x)cos(x):将分母和分子乘以 sin(x)sin(−50+3x)cos(−50+3x)cos(x)=sin(−50+3x)sin(x)cos(−50+3x)cos(x)sin(x)
=sin(x)sin(3x−50)sin(3x−50)−sin(x)sin(3x−50)sin2(x)sin(3x−50)−sin(−50+3x)sin(x)cos(−50+3x)cos(x)sin(x)
因为分母相等,所以合并分式: ca±cb=ca±b=sin(x)sin(3x−50)sin(3x−50)−sin2(x)sin(3x−50)−cos(−50+3x)cos(x)sin(x)
=sin(x)sin(3x−50)sin(3x−50)−sin2(x)sin(3x−50)−cos(−50+3x)cos(x)sin(x)
sin(−50+3x)sin(x)sin(−50+3x)−sin(−50+3x)sin2(x)−cos(−50+3x)cos(x)sin(x)=0
g(x)f(x)=0⇒f(x)=0sin(−50+3x)−sin(−50+3x)sin2(x)−cos(−50+3x)cos(x)sin(x)=0
使用三角恒等式改写
sin(−50+3x)−sin(−50+3x)sin2(x)−cos(−50+3x)cos(x)sin(x)
使用毕达哥拉斯恒等式: cos2(x)+sin2(x)=1sin2(x)=1−cos2(x)=sin(−50+3x)−sin(−50+3x)(1−cos2(x))−cos(−50+3x)cos(x)sin(x)
化简 sin(−50+3x)−sin(−50+3x)(1−cos2(x))−cos(−50+3x)cos(x)sin(x):cos2(x)sin(−50+3x)−cos(−50+3x)cos(x)sin(x)
sin(−50+3x)−sin(−50+3x)(1−cos2(x))−cos(−50+3x)cos(x)sin(x)
乘开 −sin(−50+3x)(1−cos2(x)):−sin(−50+3x)+cos2(x)sin(−50+3x)
−sin(−50+3x)(1−cos2(x))
使用分配律: a(b−c)=ab−aca=−sin(−50+3x),b=1,c=cos2(x)=−sin(−50+3x)⋅1−(−sin(−50+3x))cos2(x)
使用加减运算法则−(−a)=a=−1⋅sin(−50+3x)+cos2(x)sin(−50+3x)
乘以:1⋅sin(−50+3x)=sin(−50+3x)=−sin(−50+3x)+cos2(x)sin(−50+3x)
=sin(−50+3x)−sin(−50+3x)+cos2(x)sin(−50+3x)−cos(−50+3x)cos(x)sin(x)
同类项相加:sin(3x−50)−sin(3x−50)=0=cos2(x)sin(3x−50)−cos(3x−50)cos(x)sin(x)
=cos2(x)sin(−50+3x)−cos(−50+3x)cos(x)sin(x)
cos2(x)sin(−50+3x)−cos(−50+3x)cos(x)sin(x)=0
分解 cos2(x)sin(−50+3x)−cos(−50+3x)cos(x)sin(x):cos(x)(cos(x)sin(−50+3x)−cos(−50+3x)sin(x))
cos2(x)sin(−50+3x)−cos(−50+3x)cos(x)sin(x)
使用指数法则: ab+c=abaccos2(x)=cos(x)cos(x)=cos(x)cos(x)sin(−50+3x)−cos(−50+3x)cos(x)sin(x)
因式分解出通项 cos(x)=cos(x)(cos(x)sin(−50+3x)−cos(−50+3x)sin(x))
cos(x)(cos(x)sin(−50+3x)−cos(−50+3x)sin(x))=0
分别求解每个部分cos(x)=0orcos(x)sin(−50+3x)−cos(−50+3x)sin(x)=0
cos(x)=0:x=2π+2πn,x=23π+2πn
cos(x)=0
cos(x)=0的通解
cos(x) 周期表(周期为 2πn):
x06π4π3π2π32π43π65πcos(x)12322210−21−22−23xπ67π45π34π23π35π47π611πcos(x)−1−23−22−210212223
x=2π+2πn,x=23π+2πn
x=2π+2πn,x=23π+2πn
cos(x)sin(−50+3x)−cos(−50+3x)sin(x)=0:x=πn+25,x=2π+25+πn
cos(x)sin(−50+3x)−cos(−50+3x)sin(x)=0
使用三角恒等式改写
cos(x)sin(−50+3x)−cos(−50+3x)sin(x)
使用角差恒等式: sin(s)cos(t)−cos(s)sin(t)=sin(s−t)=sin(−50+3x−x)
sin(−50+3x−x)=0
sin(−50+3x−x)=0的通解
sin(x) 周期表(周期为 2πn"):
x06π4π3π2π32π43π65πsin(x)02122231232221xπ67π45π34π23π35π47π611πsin(x)0−21−22−23−1−23−22−21
−50+3x−x=0+2πn,−50+3x−x=π+2πn
−50+3x−x=0+2πn,−50+3x−x=π+2πn
解 −50+3x−x=0+2πn:x=πn+25
−50+3x−x=0+2πn
同类项相加:3x−x=2x−50+2x=0+2πn
0+2πn=2πn−50+2x=2πn
将 50到右边
−50+2x=2πn
两边加上 50−50+2x+50=2πn+50
化简2x=2πn+50
2x=2πn+50
两边除以 2
2x=2πn+50
两边除以 222x=22πn+250
化简
22x=22πn+250
化简 22x:x
22x
数字相除:22=1=x
化简 22πn+250:πn+25
22πn+250
数字相除:22=1=πn+250
数字相除:250=25=πn+25
x=πn+25
x=πn+25
x=πn+25
解 −50+3x−x=π+2πn:x=2π+25+πn
−50+3x−x=π+2πn
同类项相加:3x−x=2x−50+2x=π+2πn
将 50到右边
−50+2x=π+2πn
两边加上 50−50+2x+50=π+2πn+50
化简2x=π+2πn+50
2x=π+2πn+50
两边除以 2
2x=π+2πn+50
两边除以 222x=2π+22πn+250
化简
22x=2π+22πn+250
化简 22x:x
22x
数字相除:22=1=x
化简 2π+22πn+250:2π+25+πn
2π+22πn+250
对同类项分组=2π+250+22πn
数字相除:250=25=2π+25+22πn
数字相除:22=1=2π+25+πn
x=2π+25+πn
x=2π+25+πn
x=2π+25+πn
x=πn+25,x=2π+25+πn
合并所有解x=2π+2πn,x=23π+2πn,x=πn+25,x=2π+25+πn