sin(θ)=(12sin(43))/9

Lösung

sin (θ) = \frac{12 sin ( 4 3 ^{\circ} )}{9}

θ = 1.14167 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 1.14167 \dots + 36 0^{\circ} n

Radianten

θ = 1.14167 \dots + 2 πn, θ = π - 1.14167 \dots + 2 πn

Schritte zur Lösung

sin (θ) = \frac{12 sin ( 4 3 ^{\circ} )}{9}

Streiche die gemeinsamen Faktoren:

3

sin (θ) = \frac{4 sin ( 4 3 ^{\circ} )}{3}

Wende die Eigenschaften der Trigonometrie an

sin (θ) = \frac{4 sin ( 4 3 ^{\circ} )}{3}

Allgemeine Lösung für

sin (θ) = \frac{4 sin ( 4 3 ^{\circ} )}{3}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

θ = arcsin (\frac{4 sin ( 4 3 ^{\circ} )}{3}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{4 sin ( 4 3 ^{\circ} )}{3}) + 36 0^{\circ} n

θ = arcsin (\frac{4 sin ( 4 3 ^{\circ} )}{3}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{4 sin ( 4 3 ^{\circ} )}{3}) + 36 0^{\circ} n

Zeige Lösungen in Dezimalform

θ = 1.14167 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 1.14167 \dots + 36 0^{\circ} n

cos (2 x) - 7 cos (x) + 6 = 0

6 cos (2 θ) + 3 = 0

sin (3 x) - 2 = - 3 sin (3 x)

\frac{1}{cos ( x )} + sec^{2} (x) - 1 - cos (x) = 0

tan (θ) = \frac{3}{3}, 18 0^{\circ} \leq θ \leq 36 0^{\circ}