解答
sin(3652π(t+101.75))=−1
解答
t=364.99999…n+172
+1
度数
t=9854.87407…∘+20912.95952…∘n求解步骤
sin(3652π(t+101.75))=−1
sin(3652π(t+101.75))=−1的通解
sin(x) 周期表(周期为 2πn"):
x06π4π3π2π32π43π65πsin(x)02122231232221xπ67π45π34π23π35π47π611πsin(x)0−21−22−23−1−23−22−21
3652π(t+101.75)=23π+2πn
3652π(t+101.75)=23π+2πn
解 3652π(t+101.75)=23π+2πn:t=364.99999…n+172
3652π(t+101.75)=23π+2πn
在两边乘以 365
3652π(t+101.75)=23π+2πn
在两边乘以 365365365⋅2π(t+101.75)=365⋅23π+365⋅2πn
化简
365365⋅2π(t+101.75)=365⋅23π+365⋅2πn
化简 365365⋅2π(t+101.75):6.28318…(t+101.75)
365365⋅2π(t+101.75)
数字相乘:365⋅2=730=365730π(t+101.75)
数字相除:365730=2=2π(t+101.75)
数字相乘:2⋅3.14159…=6.28318…=6.28318…(t+101.75)
化简 365⋅23π+365⋅2πn:21095π+730πn
365⋅23π+365⋅2πn
365⋅23π=21095π
365⋅23π
分式相乘: a⋅cb=ca⋅b=23π365
数字相乘:3⋅365=1095=21095π
365⋅2πn=730πn
365⋅2πn
数字相乘:365⋅2=730=730πn
=21095π+730πn
6.28318…(t+101.75)=21095π+730πn
6.28318…(t+101.75)=21095π+730πn
6.28318…(t+101.75)=21095π+730πn
两边除以 6.28318…
6.28318…(t+101.75)=21095π+730πn
两边除以 6.28318…6.28318…6.28318…(t+101.75)=6.28318…21095π+6.28318…730πn
化简
6.28318…6.28318…(t+101.75)=6.28318…21095π+6.28318…730πn
化简 6.28318…6.28318…(t+101.75):t+101.75
6.28318…6.28318…(t+101.75)
约分:6.28318…=t+101.75
化简 6.28318…21095π+6.28318…730πn:273.75+364.99999…n
6.28318…21095π+6.28318…730πn
6.28318…21095π=12.56637…1095π
6.28318…21095π
使用分式法则: acb=c⋅ab=2⋅6.28318…1095π
数字相乘:2⋅6.28318…=12.56637…=12.56637…1095π
=12.56637…1095π+6.28318…730πn
12.56637…1095π=273.75
12.56637…1095π
数字相乘:1095⋅3.14159…=3440.04395…=12.56637…3440.04395…
数字相除:12.56637…3440.04395…=273.75=273.75
6.28318…730πn=364.99999…n
6.28318…730πn
数字相乘:730⋅3.14159…=2293.36263…=6.28318…2293.36263…n
数字相除:6.28318…2293.36263…=364.99999…=364.99999…n
=273.75+364.99999…n
t+101.75=273.75+364.99999…n
t+101.75=273.75+364.99999…n
t+101.75=273.75+364.99999…n
将 101.75到右边
t+101.75=273.75+364.99999…n
两边减去 101.75t+101.75−101.75=273.75+364.99999…n−101.75
化简t=364.99999…n+172
t=364.99999…n+172
t=364.99999…n+172