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受欢迎的三角函数 >

cos((2x-pi)/(17))=0

解答

cos (\frac{2 x - π}{17}) = 0

解答

x = 17 πn + \frac{π}{2} + \frac{17 π}{4}, x = 17 πn + \frac{π}{2} + \frac{51 π}{4}

+1

度数

x = 85 5^{\circ} + 306 0^{\circ} n, x = 238 5^{\circ} + 306 0^{\circ} n

求解步骤

cos (\frac{2 x - π}{17}) = 0

cos (\frac{2 x - π}{17}) = 0

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{2 x - π}{17} = \frac{π}{2} + 2 πn, \frac{2 x - π}{17} = \frac{3 π}{2} + 2 πn

\frac{2 x - π}{17} = \frac{π}{2} + 2 πn, \frac{2 x - π}{17} = \frac{3 π}{2} + 2 πn

解

\frac{2 x - π}{17} = \frac{π}{2} + 2 πn : x = 17 πn + \frac{π}{2} + \frac{17 π}{4}

\frac{2 x - π}{17} = \frac{π}{2} + 2 πn

在两边乘以

17

\frac{2 x - π}{17} = \frac{π}{2} + 2 πn

在两边乘以

17

\frac{17 ( 2 x - π )}{17} = 17 \cdot \frac{π}{2} + 17 \cdot 2 πn

化简

\frac{17 ( 2 x - π )}{17} = 17 \cdot \frac{π}{2} + 17 \cdot 2 πn

化简

\frac{17 ( 2 x - π )}{17} : 2 x - π

\frac{17 ( 2 x - π )}{17}

数字相除:

\frac{17}{17} = 1

= 2 x - π

化简

17 \cdot \frac{π}{2} + 17 \cdot 2 πn : \frac{17 π}{2} + 34 πn

17 \cdot \frac{π}{2} + 17 \cdot 2 πn

乘

17 \cdot \frac{π}{2} : \frac{17 π}{2}

17 \cdot \frac{π}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 17}{2}

= \frac{17 π}{2} + 17 \cdot 2 πn

数字相乘:

17 \cdot 2 = 34

= \frac{17 π}{2} + 34 πn

2 x - π = \frac{17 π}{2} + 34 πn

2 x - π = \frac{17 π}{2} + 34 πn

2 x - π = \frac{17 π}{2} + 34 πn

将

π

到右边

2 x - π = \frac{17 π}{2} + 34 πn

两边加上

π

2 x - π + π = \frac{17 π}{2} + 34 πn + π

化简

2 x = \frac{17 π}{2} + 34 πn + π

2 x = \frac{17 π}{2} + 34 πn + π

两边除以

2

2 x = \frac{17 π}{2} + 34 πn + π

两边除以

2

\frac{2 x}{2} = \frac{\frac{17 π}{2}}{2} + \frac{34 πn}{2} + \frac{π}{2}

化简

\frac{2 x}{2} = \frac{\frac{17 π}{2}}{2} + \frac{34 πn}{2} + \frac{π}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{17 π}{2}}{2} + \frac{34 πn}{2} + \frac{π}{2} : 17 πn + \frac{π}{2} + \frac{17 π}{4}

\frac{\frac{17 π}{2}}{2} + \frac{34 πn}{2} + \frac{π}{2}

对同类项分组

= \frac{π}{2} + \frac{34 πn}{2} + \frac{\frac{17 π}{2}}{2}

\frac{34 πn}{2} = 17 πn

\frac{34 πn}{2}

数字相除:

\frac{34}{2} = 17

= 17 πn

\frac{\frac{17 π}{2}}{2} = \frac{17 π}{4}

\frac{\frac{17 π}{2}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{17 π}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{17 π}{4}

= \frac{π}{2} + 17 πn + \frac{17 π}{4}

对同类项分组

= 17 πn + \frac{π}{2} + \frac{17 π}{4}

x = 17 πn + \frac{π}{2} + \frac{17 π}{4}

x = 17 πn + \frac{π}{2} + \frac{17 π}{4}

x = 17 πn + \frac{π}{2} + \frac{17 π}{4}

解

\frac{2 x - π}{17} = \frac{3 π}{2} + 2 πn : x = 17 πn + \frac{π}{2} + \frac{51 π}{4}

\frac{2 x - π}{17} = \frac{3 π}{2} + 2 πn

在两边乘以

17

\frac{2 x - π}{17} = \frac{3 π}{2} + 2 πn

在两边乘以

17

\frac{17 ( 2 x - π )}{17} = 17 \cdot \frac{3 π}{2} + 17 \cdot 2 πn

化简

\frac{17 ( 2 x - π )}{17} = 17 \cdot \frac{3 π}{2} + 17 \cdot 2 πn

化简

\frac{17 ( 2 x - π )}{17} : 2 x - π

\frac{17 ( 2 x - π )}{17}

数字相除:

\frac{17}{17} = 1

= 2 x - π

化简

17 \cdot \frac{3 π}{2} + 17 \cdot 2 πn : \frac{51 π}{2} + 34 πn

17 \cdot \frac{3 π}{2} + 17 \cdot 2 πn

17 \cdot \frac{3 π}{2} = \frac{51 π}{2}

17 \cdot \frac{3 π}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 π 17}{2}

数字相乘:

3 \cdot 17 = 51

= \frac{51 π}{2}

17 \cdot 2 πn = 34 πn

17 \cdot 2 πn

数字相乘:

17 \cdot 2 = 34

= 34 πn

= \frac{51 π}{2} + 34 πn

2 x - π = \frac{51 π}{2} + 34 πn

2 x - π = \frac{51 π}{2} + 34 πn

2 x - π = \frac{51 π}{2} + 34 πn

将

π

到右边

2 x - π = \frac{51 π}{2} + 34 πn

两边加上

π

2 x - π + π = \frac{51 π}{2} + 34 πn + π

化简

2 x = \frac{51 π}{2} + 34 πn + π

2 x = \frac{51 π}{2} + 34 πn + π

两边除以

2

2 x = \frac{51 π}{2} + 34 πn + π

两边除以

2

\frac{2 x}{2} = \frac{\frac{51 π}{2}}{2} + \frac{34 πn}{2} + \frac{π}{2}

化简

\frac{2 x}{2} = \frac{\frac{51 π}{2}}{2} + \frac{34 πn}{2} + \frac{π}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{51 π}{2}}{2} + \frac{34 πn}{2} + \frac{π}{2} : 17 πn + \frac{π}{2} + \frac{51 π}{4}

\frac{\frac{51 π}{2}}{2} + \frac{34 πn}{2} + \frac{π}{2}

对同类项分组

= \frac{π}{2} + \frac{34 πn}{2} + \frac{\frac{51 π}{2}}{2}

\frac{34 πn}{2} = 17 πn

\frac{34 πn}{2}

数字相除:

\frac{34}{2} = 17

= 17 πn

\frac{\frac{51 π}{2}}{2} = \frac{51 π}{4}

\frac{\frac{51 π}{2}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{51 π}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{51 π}{4}

= \frac{π}{2} + 17 πn + \frac{51 π}{4}

对同类项分组

= 17 πn + \frac{π}{2} + \frac{51 π}{4}

x = 17 πn + \frac{π}{2} + \frac{51 π}{4}

x = 17 πn + \frac{π}{2} + \frac{51 π}{4}

x = 17 πn + \frac{π}{2} + \frac{51 π}{4}

x = 17 πn + \frac{π}{2} + \frac{17 π}{4}, x = 17 πn + \frac{π}{2} + \frac{51 π}{4}

作图

流行的例子

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