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受欢迎的三角函数 >

solvefor y,-1/2 cot(y)=(t^2)/2+C

解答

求解

y, - \frac{1}{2} cot (y) = \frac{t ^{2}}{2} + C

解答

y = arccot (- t^{2} - 2 C) + πn

求解步骤

- \frac{1}{2} cot (y) = \frac{t ^{2}}{2} + C

在两边乘以

- 2

- \frac{1}{2} cot (y) = \frac{t ^{2}}{2} + C

在两边乘以

- 2

(- \frac{1}{2} cot (y)) (- 2) = \frac{t ^{2}}{2} (- 2) + C (- 2)

化简

(- \frac{1}{2} cot (y)) (- 2) = \frac{t ^{2}}{2} (- 2) + C (- 2)

化简

(- \frac{1}{2} cot (y)) (- 2) : cot (y)

(- \frac{1}{2} cot (y)) (- 2)

去除括号:

(- a) = - a, - (- a) = a

= \frac{1}{2} cot (y) \cdot 2

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2} cot (y)

约分:

2

= cot (y) \cdot 1

乘以:

cot (y) \cdot 1 = cot (y)

= cot (y)

化简

\frac{t ^{2}}{2} (- 2) + C (- 2) : - t^{2} - 2 C

\frac{t ^{2}}{2} (- 2) + C (- 2)

去除括号:

(- a) = - a

= - \frac{t ^{2}}{2} \cdot 2 - C \cdot 2

\frac{t ^{2}}{2} \cdot 2 = t^{2}

\frac{t ^{2}}{2} \cdot 2

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{t ^{2} \cdot 2}{2}

约分:

2

= t^{2}

= - t^{2} - 2 C

cot (y) = - t^{2} - 2 C

cot (y) = - t^{2} - 2 C

cot (y) = - t^{2} - 2 C

使用反三角函数性质

cot (y) = - t^{2} - 2 C

cot (y) = - t^{2} - 2 C

的通解

cot (x) = a \Rightarrow x = arccot (a) + πn

y = arccot (- t^{2} - 2 C) + πn

y = arccot (- t^{2} - 2 C) + πn

作图

流行的例子

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