m^3=5

Lösung

m^{3} = 5

m = 35, m = - 35 \frac{1}{2} + 35 \frac{3}{2} i, m = - 35 \frac{1}{2} - 35 \frac{3}{2} i

Schritte zur Lösung

m^{3} = 5

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

m = 35, m = 35 \frac{- 1 + 3 i}{2}, m = 35 \frac{- 1 - 3 i}{2}

Vereinfache

35 \frac{- 1 + 3 i}{2} : - 35 \frac{1}{2} + 35 \frac{3}{2} i

Vereinfache

35 \frac{- 1 - 3 i}{2} : - 35 \frac{1}{2} - 35 \frac{3}{2} i

m = 35, m = - 35 \frac{1}{2} + 35 \frac{3}{2} i, m = - 35 \frac{1}{2} - 35 \frac{3}{2} i

x^{3} - 4 x^{2} - 53 x + 168 = 0

x^{3} - 3 x = 1

x^{2 + 1} = 8

v^{3} = 8

m^{3} - 64 = 0