d/(dθ)(2sin(3θ))

Lösung

\frac{d}{d θ} (2 sin (3 θ))

6 cos (3 θ)

Schritte zur Lösung

\frac{d}{d θ} (2 sin (3 θ))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d θ} (sin (3 θ))

Wende die Kettenregel an:

cos (3 θ) \frac{d}{d θ} (3 θ)

= cos (3 θ) \frac{d}{d θ} (3 θ)

\frac{d}{d θ} (3 θ) = 3

= 2 cos (3 θ) \cdot 3

Vereinfache

= 6 cos (3 θ)

x \to 0 - lim (e^{\frac{2}{x}})

\int (x^{3} - 3) d x

\int x sin (7 x^{2}) cos (8 x^{2}) d x

\int y - x^{3} d x

n \to \infty lim (\frac{1}{3 n})