(\partial)/(\partial x)(-400x(y-x^2)-2(1-x))

Lösung

\frac{\partial}{\partial x} (- 400 x (y - x^{2}) - 2 (1 - x))

- 400 (y - 3 x^{2}) + 2

Schritte zur Lösung

\frac{\partial}{\partial x} (- 400 x (y - x^{2}) - 2 (1 - x))

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (400 x (y - x^{2})) - \frac{\partial}{\partial x} (2 (1 - x))

\frac{\partial}{\partial x} (400 x (y - x^{2})) = 400 (y - 3 x^{2})

\frac{\partial}{\partial x} (2 (1 - x)) = - 2

= - 400 (y - 3 x^{2}) - (- 2)

Vereinfache

= - 400 (y - 3 x^{2}) + 2

y^{^{'}} = sin (x - y)

\frac{d}{d x} (c x^{- 6})

\int (x + 1) (2 x - 1) d x

d er i v a t i v e \frac{1}{x + 6}

\int \frac{1}{x ( ln ( x ) ) ^{15}} d x