derivative x^3+5x^2-63x-140

Lösung

ableitung von

x^{3} + 5 x^{2} - 63 x - 140

3 x^{2} + 10 x - 63

Schritte zur Lösung

\frac{d}{d x} (x^{3} + 5 x^{2} - 63 x - 140)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (5 x^{2}) - \frac{d}{d x} (63 x) - \frac{d}{d x} (140)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (63 x) = 63

\frac{d}{d x} (140) = 0

= 3 x^{2} + 10 x - 63 - 0

Vereinfache

= 3 x^{2} + 10 x - 63

25 y^{^{''}} - 40 y^{^{'}} + 16 y = 0, y (0) = 3, y^{^{'}} (0) = - 2

\int cos (5 x) d (5 x) d x

d er i v a t i v e f (x) = \frac{5}{x ^{4}}

\frac{d}{d x} (4 - 2 sin (2 x - \frac{π}{4}))

\frac{\partial}{\partial x} (f (x) g (x))