derivative of sqrt(cos(3x-1))

Lösung

\frac{d}{d x} (cos (3 x - 1))

- \frac{3 sin ( 3 x - 1 )}{2 cos ( 3 x - 1 )}

Schritte zur Lösung

\frac{d}{d x} (cos (3 x - 1))

Wende die Kettenregel an:

\frac{1}{2 cos ( 3 x - 1 )} \frac{d}{d x} (cos (3 x - 1))

= \frac{1}{2 cos ( 3 x - 1 )} \frac{d}{d x} (cos (3 x - 1))

\frac{d}{d x} (cos (3 x - 1)) = - sin (3 x - 1) \cdot 3

= \frac{1}{2 cos ( 3 x - 1 )} (- sin (3 x - 1) \cdot 3)

Vereinfache

\frac{1}{2 cos ( 3 x - 1 )} (- sin (3 x - 1) \cdot 3) : - \frac{3 sin ( 3 x - 1 )}{2 cos ( 3 x - 1 )}

= - \frac{3 sin ( 3 x - 1 )}{2 cos ( 3 x - 1 )}

y^{^{''}} + 4 y = 0, y (0) = 5, y^{^{'}} (0) = 1

\int_{0}^{s} \frac{1}{0.2 s + 10} d s

\frac{\partial}{\partial x} (3 x^{2} - 4 x y + x yz)

y^{^{'}} = x^{2} - 2

\int \frac{4 x}{x - 1} d x