y^'=x^2-2

Lösung

y^{^{'}} = x^{2} - 2

y = \frac{x ^{3}}{3} - 2 x + c_{1}

Schritte zur Lösung

y^{'} (x) = x^{2} - 2

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int x^{2} - 2 d x

\int x^{2} - 2 d x = \frac{x ^{3}}{3} - 2 x + c_{1}

y = \frac{x ^{3}}{3} - 2 x + c_{1}

\int \frac{4 x}{x - 1} d x

y^{^{'}} = 5 t y^{2}

d er i v a t i v e 9 x^{- 2}

d er i v a t i v e y = \frac{x}{1 - ln ( x - 5 )}

\frac{d}{d x} (\frac{x cos ( x ) + π}{x - π})