integral of e^{4x}+2x^{1/4}

Lösung

\int e^{4 x} + 2 x^{\frac{1}{4}} d x

\frac{1}{4} e^{4 x} + \frac{8}{5} x^{\frac{5}{4}} + C

Schritte zur Lösung

\int e^{4 x} + 2 x^{\frac{1}{4}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{4 x} d x + \int 2 x^{\frac{1}{4}} d x

\int e^{4 x} d x = \frac{1}{4} e^{4 x}

\int 2 x^{\frac{1}{4}} d x = \frac{8}{5} x^{\frac{5}{4}}

= \frac{1}{4} e^{4 x} + \frac{8}{5} x^{\frac{5}{4}}

Füge eine Konstante zur Lösung hinzu

= \frac{1}{4} e^{4 x} + \frac{8}{5} x^{\frac{5}{4}} + C

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