integral of (x^2+8)/(x(x+2)^2)

Lösung

\int \frac{x ^{2} + 8}{x ( x + 2 ) ^{2}} d x

- ln ∣ x + 2 ∣ + \frac{6}{x + 2} + 2 ln ∣ x ∣ + C

Schritte zur Lösung

\int \frac{x ^{2} + 8}{x ( x + 2 ) ^{2}} d x

Multipliziere aus

\frac{x ^{2} + 8}{x ( x + 2 ) ^{2}} : \frac{x ^{2}}{x ( x + 2 ) ^{2}} + \frac{8}{x ( x + 2 ) ^{2}}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{2}}{x ( x + 2 ) ^{2}} d x + \int \frac{8}{x ( x + 2 ) ^{2}} d x

\int \frac{x ^{2}}{x ( x + 2 ) ^{2}} d x = ln ∣ x + 2 ∣ + \frac{2}{x + 2}

\int \frac{8}{x ( x + 2 ) ^{2}} d x = 8 (\frac{1}{4} ln ∣ x ∣ - \frac{1}{4} ln ∣ x + 2 ∣ + \frac{1}{2 ( x + 2 )})

= ln ∣ x + 2 ∣ + \frac{2}{x + 2} + 8 (\frac{1}{4} ln ∣ x ∣ - \frac{1}{4} ln ∣ x + 2 ∣ + \frac{1}{2 ( x + 2 )})

Vereinfache

ln ∣ x + 2 ∣ + \frac{2}{x + 2} + 8 (\frac{1}{4} ln ∣ x ∣ - \frac{1}{4} ln ∣ x + 2 ∣ + \frac{1}{2 ( x + 2 )}) : - ln ∣ x + 2 ∣ + \frac{6}{x + 2} + 2 ln ∣ x ∣

= - ln ∣ x + 2 ∣ + \frac{6}{x + 2} + 2 ln ∣ x ∣

Füge eine Konstante zur Lösung hinzu

= - ln ∣ x + 2 ∣ + \frac{6}{x + 2} + 2 ln ∣ x ∣ + C

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