integral from 1 to 2 of (25x^3+6/(x^2))

解

\int_{1}^{2} (25 x^{3} + \frac{6}{x ^{2}}) d x

\frac{387}{4}

十進法表記

96.75

解答ステップ

\int_{1}^{2} 25 x^{3} + \frac{6}{x ^{2}} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 25 x^{3} d x + \int_{1}^{2} \frac{6}{x ^{2}} d x

\int_{1}^{2} 25 x^{3} d x = \frac{375}{4}

\int_{1}^{2} \frac{6}{x ^{2}} d x = 3

= \frac{375}{4} + 3

簡素化

\frac{375}{4} + 3 : \frac{387}{4}

= \frac{387}{4}