integral from 2 to 6 of x^2+1

Lösung

\int_{2}^{6} x^{2} + 1 d x

\frac{220}{3}

Dezimale

73.33333 \dots

Schritte zur Lösung

\int_{2}^{6} x^{2} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{6} x^{2} d x + \int_{2}^{6} 1 d x

\int_{2}^{6} x^{2} d x = \frac{208}{3}

\int_{2}^{6} 1 d x = 4

= \frac{208}{3} + 4

Vereinfache

\frac{208}{3} + 4 : \frac{220}{3}

= \frac{220}{3}

d er i v a t i v e - \frac{1}{x} - \frac{1}{x ^{2}} + \frac{1}{x ^{3}}

in v erse l a pl a ce \frac{s + 1}{s ( s + 2 ) ( s + 4 )}

in v erse l a pl a ce \frac{1}{s ^{2} ( s - 3 ) ^{2}}

\int \frac{1}{t - 2} d t

\int \frac{3 x ^{3}}{4 - x ^{2}} d x