x^2y^'+2xy=sin(3x)

Lösung

x^{2} y^{^{'}} + 2 x y = sin (3 x)

y = - \frac{cos ( 3 x )}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

Schritte zur Lösung

x^{2} y^{'} (x) + 2 x y = sin (3 x)

Solve linear ODE:

y = - \frac{cos ( 3 x )}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

y = - \frac{cos ( 3 x )}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

x \to 0 - lim (\frac{x + 94}{x})

\frac{d}{d t} (\frac{2 t}{t ^{2} + 1})

h \to 0 lim ((2 h)^{2})

t an g e n t y = 8 e^{x} cos^{2} (x), at x = \frac{π}{4}

\frac{\partial}{\partial x} (- 2 cos (- 3 x + 7))