y^'=((3x^2-e^x))/(2y-5)

Lösung

y^{^{'}} = \frac{( 3 x ^{2} - e ^{x} )}{2 y - 5}

y = \frac{5 + 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}, y = \frac{5 - 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}

Schritte zur Lösung

y^{'} (x) = \frac{( 3 x ^{2} - e ^{x} )}{2 y - 5}

Solve separable ODE:

y = \frac{5 + 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}, y = \frac{5 - 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}

y = \frac{5 + 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}, y = \frac{5 - 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}