5x^2=cy(x)

Lösung

5 x^{2} = cy

(h, k) = (0, 0), p = \frac{c}{20}

Schritte zur Lösung

5 x^{2} = cy

Rewrite

5 x^{2} = cy

in the standard form:

4 \cdot \frac{c}{20} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{c}{20}