exzentrizität (x^2)/(16)+(y^2)/(36)=1

Lösung

exzentrizität

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

\frac{5}{3}

Dezimale

0.74535 \dots

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 6, a = 4

= \frac{6 ^{2} - 4 ^{2}}{6}

\frac{6 ^{2} - 4 ^{2}}{6} = \frac{5}{3}

= \frac{5}{3}

ecce n t r i c i t y \frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1

ecce n t r i c i t y 10 x^{2} + 5 y^{2} = 50

ecce n t r i c i t y \frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

ecce n t r i c i t y 4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

ecce n t r i c i t y 4 x^{2} + 3 y^{2} - 8 x + 18 y + 19 = 0