cos(θ)=(sqrt(3))/4

Lösung

cos (θ) = \frac{3}{4}

θ = 1.12296 \dots + 2 πn, θ = 2 π - 1.12296 \dots + 2 πn

Grad

θ = 64.34109 \dots^{\circ} + 36 0^{\circ} n, θ = 295.65890 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{3}{4}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{3}{4}

Allgemeine Lösung für

cos (θ) = \frac{3}{4}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{3}{4}) + 2 πn, θ = 2 π - arccos (\frac{3}{4}) + 2 πn

θ = arccos (\frac{3}{4}) + 2 πn, θ = 2 π - arccos (\frac{3}{4}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 1.12296 \dots + 2 πn, θ = 2 π - 1.12296 \dots + 2 πn

cos (x) = \frac{- 3}{5}

so l v e f or x, sin (2 x) = - \frac{1}{2}

9 cos (2 θ) = 27 cos (θ) - 18

4 csc (x) = 3 csc (x) cot (x) + 3 csc (x)

4 cos^{2} (x) + 4 cos (x) = 1, 0^{\circ} \leq x < 36 0^{\circ}