beweisen cos(α-β)=cos(α)cos(β)+sin(α)sin(β)

Lösung

beweisen

cos (α - β) = cos (α) cos (β) + sin (α) sin (β)

Wahr

Schritte zur Lösung

cos (α - β) = cos (α) cos (β) + sin (α) sin (β)

Benutze die Winkel-Differenz-Identität:

cos (s - t) = cos (s) cos (t) + sin (s) sin (t)

\Rightarrow Wahr

p ro v e cos^{2} (x) - sin^{2} (x) = 1 - sin^{2} (x)

p ro v e sin^{3} (x) = \frac{3}{4} sin (x) - \frac{1}{4} sin (3 x)

p ro v e cos^{2} (x) = (1 - sin (x)) (1 + sin (x))

p ro v e \frac{( cos ( x ) sec ( x ) )}{tan ( x )} = cot (x)

p ro v e (sin^{2} (x) + cos^{2} (x))^{5} = 1