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Beliebt Trigonometrie >

solvefor t,x=arccos(1/(sqrt(1+t^2)))

Lösung

löse nach

t, x = arccos (\frac{1}{1 + t ^{2}})

Lösung

t = \frac{1 - cos ^{2} ( x )}{cos ( x )}, t = - \frac{1 - cos ^{2} ( x )}{cos ( x )}

Schritte zur Lösung

x = arccos (\frac{1}{1 + t ^{2}})

Tausche die Seiten

arccos (\frac{1}{1 + t ^{2}}) = x

Wende die Eigenschaften der Trigonometrie an

arccos (\frac{1}{1 + t ^{2}}) = x

arccos (x) = a \Rightarrow x = cos (a)

\frac{1}{1 + t ^{2}} = cos (x)

\frac{1}{1 + t ^{2}} = cos (x)

Löse

\frac{1}{1 + t ^{2}} = cos (x) : t = \frac{1 - cos ^{2} ( x )}{cos ( x )} {x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn}, t = - \frac{1 - cos ^{2} ( x )}{cos ( x )} {x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn}

\frac{1}{1 + t ^{2}} = cos (x)

Multipliziere beide Seiten mit

1 + t^{2}

\frac{1}{1 + t ^{2}} 1 + t^{2} = cos (x) 1 + t^{2}

Vereinfache

1 = cos (x) 1 + t^{2}

Tausche die Seiten

cos (x) 1 + t^{2} = 1

Teile beide Seiten durch

cos (x)

cos (x) 1 + t^{2} = 1

Teile beide Seiten durch

cos (x)

\frac{cos ( x ) 1 + t ^{2}}{cos ( x )} = \frac{1}{cos ( x )}

Vereinfache

1 + t^{2} = \frac{1}{cos ( x )}

1 + t^{2} = \frac{1}{cos ( x )}

Quadriere beide Seiten:

1 + t^{2} = \frac{1}{cos ^{2} ( x )}

1 + t^{2} = \frac{1}{cos ( x )}

(1 + t^{2})^{2} = (\frac{1}{cos ( x )})^{2}

Schreibe

(1 + t^{2})^{2}

um:

1 + t^{2}

(1 + t^{2})^{2}

Wende Radikal Regel an:

a = a^{\frac{1}{2}}

= ((1 + t^{2})^{\frac{1}{2}})^{2}

Wende Exponentenregel an:

(a^{b})^{c} = a^{b c}

= (1 + t^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Streiche die gemeinsamen Faktoren:

2

= 1

= 1 + t^{2}

Schreibe

(\frac{1}{cos ( x )})^{2}

um:

\frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2}

Wende Exponentenregel an:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cos ^{2} ( x )}

Wende Regel an

1^{a} = 1

1^{2} = 1

= \frac{1}{cos ^{2} ( x )}

1 + t^{2} = \frac{1}{cos ^{2} ( x )}

1 + t^{2} = \frac{1}{cos ^{2} ( x )}

Löse

1 + t^{2} = \frac{1}{cos ^{2} ( x )} : t = \frac{1 - cos ^{2} ( x )}{cos ( x )}, t = - \frac{1 - cos ^{2} ( x )}{cos ( x )}

1 + t^{2} = \frac{1}{cos ^{2} ( x )}

Verschiebe

1

auf die rechte Seite

1 + t^{2} = \frac{1}{cos ^{2} ( x )}

Subtrahiere

1

von beiden Seiten

1 + t^{2} - 1 = \frac{1}{cos ^{2} ( x )} - 1

Vereinfache

t^{2} = \frac{1}{cos ^{2} ( x )} - 1

t^{2} = \frac{1}{cos ^{2} ( x )} - 1

Für

x^{2} = f (a)

sind die Lösungen

x = f (a), - f (a)

t = \frac{1}{cos ^{2} ( x )} - 1, t = - \frac{1}{cos ^{2} ( x )} - 1

Vereinfache

\frac{1}{cos ^{2} ( x )} - 1 : \frac{1 - cos ^{2} ( x )}{cos ( x )}

\frac{1}{cos ^{2} ( x )} - 1

Füge

\frac{1}{cos ^{2} ( x )} - 1

zusammen:

\frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )}

\frac{1}{cos ^{2} ( x )} - 1

Wandle das Element in einen Bruch um:

1 = \frac{1 cos ^{2} ( x )}{cos ^{2} ( x )}

= \frac{1}{cos ^{2} ( x )} - \frac{1 \cdot cos ^{2} ( x )}{cos ^{2} ( x )}

Da die Nenner gleich sind, fasse die Brüche zusammen.:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 - 1 \cdot cos ^{2} ( x )}{cos ^{2} ( x )}

Multipliziere:

1 \cdot cos^{2} (x) = cos^{2} (x)

= \frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )}

= \frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )}

Wende Radikal Regel an:

angenommen

a \geq 0, b \geq 0

= \frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )}

Wende Radikal Regel an:

angenommen

a \geq 0

cos^{2} (x) = cos (x)

= \frac{1 - cos ^{2} ( x )}{cos ( x )}

Vereinfache

- \frac{1}{cos ^{2} ( x )} - 1 : - \frac{1 - cos ^{2} ( x )}{cos ( x )}

- \frac{1}{cos ^{2} ( x )} - 1

Füge

\frac{1}{cos ^{2} ( x )} - 1

zusammen:

\frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )}

\frac{1}{cos ^{2} ( x )} - 1

Wandle das Element in einen Bruch um:

1 = \frac{1 cos ^{2} ( x )}{cos ^{2} ( x )}

= \frac{1}{cos ^{2} ( x )} - \frac{1 \cdot cos ^{2} ( x )}{cos ^{2} ( x )}

Da die Nenner gleich sind, fasse die Brüche zusammen.:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 - 1 \cdot cos ^{2} ( x )}{cos ^{2} ( x )}

Multipliziere:

1 \cdot cos^{2} (x) = cos^{2} (x)

= \frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )}

= - \frac{- cos ^{2} ( x ) + 1}{cos ^{2} ( x )}

Vereinfache

\frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )} : \frac{1 - cos ^{2} ( x )}{cos ( x )}

\frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )}

Wende Radikal Regel an:

angenommen

a \geq 0, b \geq 0

= \frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )}

Wende Radikal Regel an:

angenommen

a \geq 0

cos^{2} (x) = cos (x)

= \frac{1 - cos ^{2} ( x )}{cos ( x )}

= - \frac{- cos ^{2} ( x ) + 1}{cos ( x )}

= - \frac{1 - cos ^{2} ( x )}{cos ( x )}

t = \frac{1 - cos ^{2} ( x )}{cos ( x )}, t = - \frac{1 - cos ^{2} ( x )}{cos ( x )}

t = \frac{1 - cos ^{2} ( x )}{cos ( x )}, t = - \frac{1 - cos ^{2} ( x )}{cos ( x )}

Überprüfe die Lösungen:

t = \frac{1 - cos ^{2} ( x )}{cos ( x )} {x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn}, t = - \frac{1 - cos ^{2} ( x )}{cos ( x )} {x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn}

Überprüfe die Lösungen, in dem die sie in

\frac{1}{1 + t ^{2}} = cos (x)

einsetzt und entferne die Lösungen, die mit der Gleichung nicht übereinstimmen.

Setze ein

t = \frac{1 - cos ^{2} ( x )}{cos ( x )} : \frac{1}{1 + ( \frac{1 - c o s ^{2} ( x )}{c o s ( x )} ) ^{2}} = cos (x) \Rightarrow x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

\frac{1}{1 + ( \frac{1 - c o s ^{2} ( x )}{c o s ( x )} ) ^{2}} = cos (x)

Löse mit Substitution

\frac{1}{1 + ( \frac{1 - c o s ^{2} ( x )}{c o s ( x )} ) ^{2}} = cos (x)

Angenommen:

cos (x) = u

\frac{1}{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}} = u

\frac{1}{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}} = u : u = 1

\frac{1}{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}} = u

Multipliziere beide Seiten mit

1 + (\frac{1 - u ^{2}}{u})^{2}

\frac{1}{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}} 1 + (\frac{1 - u ^{2}}{u})^{2} = u 1 + (\frac{1 - u ^{2}}{u})^{2}

Vereinfache

1 = u 1 + (\frac{1 - u ^{2}}{u})^{2}

Quadriere beide Seiten:

1 = 1

1 = u 1 + (\frac{1 - u ^{2}}{u})^{2}

1^{2} = u 1 + (\frac{1 - u ^{2}}{u})^{2}^{2}

Schreibe

1^{2}

um:

1

1^{2}

Wende Regel an

1^{a} = 1

= 1

Schreibe

u 1 + (\frac{1 - u ^{2}}{u})^{2}^{2}

um:

1

u 1 + (\frac{1 - u ^{2}}{u})^{2}^{2}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

= u^{2} 1 + (\frac{1 - u ^{2}}{u})^{2}^{2}

1 + (\frac{1 - u ^{2}}{u})^{2}^{2} : 1 + (\frac{1 - u ^{2}}{u})^{2}

Wende Radikal Regel an:

a = a^{\frac{1}{2}}

= 1 + (\frac{1 - u ^{2}}{u})^{2}^{\frac{1}{2}}^{2}

Wende Exponentenregel an:

(a^{b})^{c} = a^{b c}

= 1 + (\frac{1 - u ^{2}}{u})^{2}^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Streiche die gemeinsamen Faktoren:

2

= 1

= 1 + (\frac{1 - u ^{2}}{u})^{2}

= u^{2} 1 + (\frac{1 - u ^{2}}{u})^{2}

Schreibe

1 + (\frac{1 - u ^{2}}{u})^{2} u^{2}

um:

1

1 + (\frac{1 - u ^{2}}{u})^{2} u^{2}

(\frac{1 - u ^{2}}{u})^{2} = \frac{1 - u ^{2}}{u ^{2}}

(\frac{1 - u ^{2}}{u})^{2}

Wende Exponentenregel an:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 1 - u ^{2} ) ^{2}}{u ^{2}}

(1 - u^{2})^{2} : 1 - u^{2}

Wende Radikal Regel an:

a = a^{\frac{1}{2}}

= ((1 - u^{2})^{\frac{1}{2}})^{2}

Wende Exponentenregel an:

(a^{b})^{c} = a^{b c}

= (1 - u^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Streiche die gemeinsamen Faktoren:

2

= 1

= 1 - u^{2}

= \frac{1 - u ^{2}}{u ^{2}}

= u^{2} (\frac{- u ^{2} + 1}{u ^{2}} + 1)

= u^{2} (1 + \frac{1 - u ^{2}}{u ^{2}})

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = u^{2}, b = 1, c = \frac{1 - u ^{2}}{u ^{2}}

= u^{2} \cdot 1 + u^{2} \frac{1 - u ^{2}}{u ^{2}}

= 1 \cdot u^{2} + \frac{1 - u ^{2}}{u ^{2}} u^{2}

Vereinfache

1 \cdot u^{2} + \frac{1 - u ^{2}}{u ^{2}} u^{2} : 1

1 \cdot u^{2} + \frac{1 - u ^{2}}{u ^{2}} u^{2}

1 \cdot u^{2} = u^{2}

1 \cdot u^{2}

Multipliziere:

1 \cdot u^{2} = u^{2}

= u^{2}

\frac{1 - u ^{2}}{u ^{2}} u^{2} = 1 - u^{2}

\frac{1 - u ^{2}}{u ^{2}} u^{2}

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 1 - u ^{2} ) u ^{2}}{u ^{2}}

Streiche die gemeinsamen Faktoren:

u^{2}

= 1 - u^{2}

= u^{2} + 1 - u^{2}

Fasse gleiche Terme zusammen

= u^{2} - u^{2} + 1

Addiere gleiche Elemente:

u^{2} - u^{2} = 0

= 1

= 1

= 1

1 = 1

1 = 1

Beide Seiten sind gleich

Wahr f \overset{u}{¨} r alle u

Überprüfe die Lösungen:

u < - 1

Falsch

, u = - 1

Falsch

, - 1 < u < 1

Falsch

, u = 1

Wahr

, u > 1

Falsch

Überprüfe die Lösungen, in dem die sie in

\frac{1}{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}} = u

einsetzt und entferne die Lösungen, die mit der Gleichung nicht übereinstimmen.

Setze ein

u < - 1 : \frac{1}{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}} \neq = u \Rightarrow

falsch

Deshalb ist die Lösung

u = 1

Setze in

u = cos (x)

ein

cos (x) = 1

cos (x) = 1

cos (x) = u = 1 : x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

cos (x) = u = 1

Wende die Eigenschaften der Trigonometrie an

cos (x) = u = 1

Allgemeine Lösung für

cos (x) = u = 1

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

Kombiniere alle Lösungen

x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

Setze ein

t = - \frac{1 - cos ^{2} ( x )}{cos ( x )} : \frac{1}{1 + ( - \frac{1 - c o s ^{2} ( x )}{c o s ( x )} ) ^{2}} = cos (x) \Rightarrow x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

\frac{1}{1 + ( - \frac{1 - c o s ^{2} ( x )}{c o s ( x )} ) ^{2}} = cos (x)

Löse mit Substitution

\frac{1}{1 + ( - \frac{1 - c o s ^{2} ( x )}{c o s ( x )} ) ^{2}} = cos (x)

Angenommen:

cos (x) = u

\frac{1}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}} = u

\frac{1}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}} = u : u = 1

\frac{1}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}} = u

Multipliziere beide Seiten mit

1 + (\frac{1 - u ^{2}}{u})^{2}

\frac{1}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}} 1 + (\frac{1 - u ^{2}}{u})^{2} = u 1 + (\frac{1 - u ^{2}}{u})^{2}

Vereinfache

\frac{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}} = u 1 + (\frac{1 - u ^{2}}{u})^{2}

Schreibe

\frac{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}}

um:

1

\frac{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}}

Fasse gleiche Potenzen zusammen:

\frac{x}{y} = \frac{x}{y}

= \frac{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}}

Schreibe

\frac{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}}

um:

1

\frac{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}}

\frac{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}} = 1

\frac{1 + ( \frac{1 - u ^{2}}{u} ) ^{2}}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}}

1 + (- \frac{1 - u ^{2}}{u})^{2} = 1 + (\frac{1 - u ^{2}}{u})^{2}

1 + (- \frac{1 - u ^{2}}{u})^{2}

Wende Exponentenregel an:

(- a)^{n} = a^{n},

wenn

n

gerade ist

(- \frac{- u ^{2} + 1}{u})^{2} = (\frac{1 - u ^{2}}{u})^{2}

= 1 + (\frac{- u ^{2} + 1}{u})^{2}

= \frac{1 + ( \frac{- u ^{2} + 1}{u} ) ^{2}}{1 + ( \frac{- u ^{2} + 1}{u} ) ^{2}}

Wende Regel an

\frac{a}{a} = 1

= 1

= 1

Wende Regel an

1 = 1

= 1

= 1

1 = u 1 + (\frac{1 - u ^{2}}{u})^{2}

Quadriere beide Seiten:

1 = 1

1 = u 1 + (\frac{1 - u ^{2}}{u})^{2}

1^{2} = u 1 + (\frac{1 - u ^{2}}{u})^{2}^{2}

Schreibe

1^{2}

um:

1

1^{2}

Wende Regel an

1^{a} = 1

= 1

Schreibe

u 1 + (\frac{1 - u ^{2}}{u})^{2}^{2}

um:

1

u 1 + (\frac{1 - u ^{2}}{u})^{2}^{2}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

= u^{2} 1 + (\frac{1 - u ^{2}}{u})^{2}^{2}

1 + (\frac{1 - u ^{2}}{u})^{2}^{2} : 1 + (\frac{1 - u ^{2}}{u})^{2}

Wende Radikal Regel an:

a = a^{\frac{1}{2}}

= 1 + (\frac{1 - u ^{2}}{u})^{2}^{\frac{1}{2}}^{2}

Wende Exponentenregel an:

(a^{b})^{c} = a^{b c}

= 1 + (\frac{1 - u ^{2}}{u})^{2}^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Streiche die gemeinsamen Faktoren:

2

= 1

= 1 + (\frac{1 - u ^{2}}{u})^{2}

= u^{2} 1 + (\frac{1 - u ^{2}}{u})^{2}

Schreibe

1 + (\frac{1 - u ^{2}}{u})^{2} u^{2}

um:

1

1 + (\frac{1 - u ^{2}}{u})^{2} u^{2}

(\frac{1 - u ^{2}}{u})^{2} = \frac{1 - u ^{2}}{u ^{2}}

(\frac{1 - u ^{2}}{u})^{2}

Wende Exponentenregel an:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 1 - u ^{2} ) ^{2}}{u ^{2}}

(1 - u^{2})^{2} : 1 - u^{2}

Wende Radikal Regel an:

a = a^{\frac{1}{2}}

= ((1 - u^{2})^{\frac{1}{2}})^{2}

Wende Exponentenregel an:

(a^{b})^{c} = a^{b c}

= (1 - u^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Streiche die gemeinsamen Faktoren:

2

= 1

= 1 - u^{2}

= \frac{1 - u ^{2}}{u ^{2}}

= u^{2} (\frac{- u ^{2} + 1}{u ^{2}} + 1)

= u^{2} (1 + \frac{1 - u ^{2}}{u ^{2}})

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = u^{2}, b = 1, c = \frac{1 - u ^{2}}{u ^{2}}

= u^{2} \cdot 1 + u^{2} \frac{1 - u ^{2}}{u ^{2}}

= 1 \cdot u^{2} + \frac{1 - u ^{2}}{u ^{2}} u^{2}

Vereinfache

1 \cdot u^{2} + \frac{1 - u ^{2}}{u ^{2}} u^{2} : 1

1 \cdot u^{2} + \frac{1 - u ^{2}}{u ^{2}} u^{2}

1 \cdot u^{2} = u^{2}

1 \cdot u^{2}

Multipliziere:

1 \cdot u^{2} = u^{2}

= u^{2}

\frac{1 - u ^{2}}{u ^{2}} u^{2} = 1 - u^{2}

\frac{1 - u ^{2}}{u ^{2}} u^{2}

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 1 - u ^{2} ) u ^{2}}{u ^{2}}

Streiche die gemeinsamen Faktoren:

u^{2}

= 1 - u^{2}

= u^{2} + 1 - u^{2}

Fasse gleiche Terme zusammen

= u^{2} - u^{2} + 1

Addiere gleiche Elemente:

u^{2} - u^{2} = 0

= 1

= 1

= 1

1 = 1

1 = 1

Beide Seiten sind gleich

Wahr f \overset{u}{¨} r alle u

Überprüfe die Lösungen:

u < - 1

Falsch

, u = - 1

Falsch

, - 1 < u < 1

Falsch

, u = 1

Wahr

, u > 1

Falsch

Überprüfe die Lösungen, in dem die sie in

\frac{1}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}} = u

einsetzt und entferne die Lösungen, die mit der Gleichung nicht übereinstimmen.

Setze ein

u < - 1 : \frac{1}{1 + ( - \frac{1 - u ^{2}}{u} ) ^{2}} \neq = u \Rightarrow

falsch

Deshalb ist die Lösung

u = 1

Setze in

u = cos (x)

ein

cos (x) = 1

cos (x) = 1

cos (x) = u = 1 : x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

cos (x) = u = 1

Wende die Eigenschaften der Trigonometrie an

cos (x) = u = 1

Allgemeine Lösung für

cos (x) = u = 1

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

Kombiniere alle Lösungen

x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn

Die Lösungen sind

t = \frac{1 - cos ^{2} ( x )}{cos ( x )} {x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn}, t = - \frac{1 - cos ^{2} ( x )}{cos ( x )} {x = arccos (u = 1) + 2 πn, x = - arccos (u = 1) + 2 πn}

t = \frac{1 - cos ^{2} ( x )}{cos ( x )}, t = - \frac{1 - cos ^{2} ( x )}{cos ( x )}

Graph

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