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人気のある三角関数 >

9cos^2(x)-18cos(x)+9=0

解

9 cos^{2} (x) - 18 cos (x) + 9 = 0

解

x = 2 πn

+1

度

x = 0^{\circ} + 36 0^{\circ} n

解答ステップ

9 cos^{2} (x) - 18 cos (x) + 9 = 0

置換で解く

9 cos^{2} (x) - 18 cos (x) + 9 = 0

仮定:

cos (x) = u

9 u^{2} - 18 u + 9 = 0

9 u^{2} - 18 u + 9 = 0 : u = 1

9 u^{2} - 18 u + 9 = 0

解くとthe二次式

9 u^{2} - 18 u + 9 = 0

二次Equationの公式:

次の場合:

a = 9, b = - 18, c = 9

u_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 9}{2 \cdot 9}

u_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 9}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 9 = 0

(- 18)^{2} - 4 \cdot 9 \cdot 9

指数の規則を適用する:

n

が偶数であれば

(- a)^{n} = a^{n}

(- 18)^{2} = 1 8^{2}

= 1 8^{2} - 4 \cdot 9 \cdot 9

数を乗じる:

4 \cdot 9 \cdot 9 = 324

= 1 8^{2} - 324

1 8^{2} = 324

= 324 - 324

数を引く:

324 - 324 = 0

= 0

u_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 9}

u = \frac{- ( - 18 )}{2 \cdot 9}

\frac{- ( - 18 )}{2 \cdot 9} = 1

\frac{- ( - 18 )}{2 \cdot 9}

規則を適用

- (- a) = a

= \frac{18}{2 \cdot 9}

数を乗じる:

2 \cdot 9 = 18

= \frac{18}{18}

規則を適用

\frac{a}{a} = 1

= 1

u = 1

二次equationの解:

u = 1

代用を戻す

u = cos (x)

cos (x) = 1

cos (x) = 1

cos (x) = 1 : x = 2 πn

cos (x) = 1

以下の一般解

cos (x) = 1

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

解く

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

すべての解を組み合わせる

x = 2 πn

グラフ

人気の例

sin (a) = - \frac{5}{13}

sin (x) = \frac{13}{14}

sin(x-pi/2)+sin(pi/2)=sin(x+pi/2)

sin (x - \frac{π}{2}) + sin (\frac{π}{2}) = sin (x + \frac{π}{2})

cos (y) = 0.8192

solvefor x,1.56sin(2x)=2*sin(x)cos(x)

so l v e f or x, 1.56 sin (2 x) = 2 \cdot sin (x) cos (x)