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sin(2θ)=2cos(θ)

Solução

sin (2 θ) = 2 cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Graus

θ = 9 0^{\circ} + 36 0^{\circ} n, θ = 27 0^{\circ} + 36 0^{\circ} n

Passos da solução

sin (2 θ) = 2 cos (θ)

Subtrair

2 cos (θ)

de ambos os lados

sin (2 θ) - 2 cos (θ) = 0

Reeecreva usando identidades trigonométricas

sin (2 θ) - 2 cos (θ)

Utilizar a identidade trigonométrica do arco duplo:

sin (2 x) = 2 sin (x) cos (x)

= 2 sin (θ) cos (θ) - 2 cos (θ)

- 2 cos (θ) + 2 cos (θ) sin (θ) = 0

Fatorar

- 2 cos (θ) + 2 cos (θ) sin (θ) : 2 cos (θ) (sin (θ) - 1)

- 2 cos (θ) + 2 cos (θ) sin (θ)

Fatorar o termo comum

2 cos (θ)

= 2 cos (θ) (- 1 + sin (θ))

2 cos (θ) (sin (θ) - 1) = 0

Resolver cada parte separadamente

cos (θ) = 0 or sin (θ) - 1 = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

cos (θ) = 0

Soluções gerais para

cos (θ) = 0

cos (x)

tabela de periodicidade com ciclo de

2 πn

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sin (θ) - 1 = 0 : θ = \frac{π}{2} + 2 πn

sin (θ) - 1 = 0

Mova

1

para o lado direito

sin (θ) - 1 = 0

Adicionar

1

a ambos os lados

sin (θ) - 1 + 1 = 0 + 1

Simplificar

sin (θ) = 1

sin (θ) = 1

Soluções gerais para

sin (θ) = 1

sin (x)

tabela de periodicidade com ciclo de

2 πn

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = \frac{π}{2} + 2 πn

θ = \frac{π}{2} + 2 πn

Combinar toda as soluções

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn