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受欢迎的三角函数 >

1/2 sin(t)-1/2 =-1

解答

\frac{1}{2} sin (t) - \frac{1}{2} = - 1

解答

t = \frac{3 π}{2} + 2 πn

+1

度数

t = 27 0^{\circ} + 36 0^{\circ} n

求解步骤

\frac{1}{2} sin (t) - \frac{1}{2} = - 1

将

\frac{1}{2}

到右边

\frac{1}{2} sin (t) - \frac{1}{2} = - 1

两边加上

\frac{1}{2}

\frac{1}{2} sin (t) - \frac{1}{2} + \frac{1}{2} = - 1 + \frac{1}{2}

化简

\frac{1}{2} sin (t) - \frac{1}{2} + \frac{1}{2} = - 1 + \frac{1}{2}

化简

\frac{1}{2} sin (t) - \frac{1}{2} + \frac{1}{2} : \frac{1}{2} sin (t)

\frac{1}{2} sin (t) - \frac{1}{2} + \frac{1}{2}

同类项相加:

- \frac{1}{2} + \frac{1}{2} = 0

= \frac{1}{2} sin (t)

化简

- 1 + \frac{1}{2} : - \frac{1}{2}

- 1 + \frac{1}{2}

将项转换为分式:

1 = \frac{1 \cdot 2}{2}

= - \frac{1 \cdot 2}{2} + \frac{1}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 2 + 1}{2}

- 1 \cdot 2 + 1 = - 1

- 1 \cdot 2 + 1

数字相乘:

1 \cdot 2 = 2

= - 2 + 1

数字相加/相减:

- 2 + 1 = - 1

= - 1

= \frac{- 1}{2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

\frac{1}{2} sin (t) = - \frac{1}{2}

\frac{1}{2} sin (t) = - \frac{1}{2}

\frac{1}{2} sin (t) = - \frac{1}{2}

在两边乘以

2

\frac{1}{2} sin (t) = - \frac{1}{2}

在两边乘以

2

2 \cdot \frac{1}{2} sin (t) = 2 (- \frac{1}{2})

化简

2 \cdot \frac{1}{2} sin (t) = 2 (- \frac{1}{2})

化简

2 \cdot \frac{1}{2} sin (t) : sin (t)

2 \cdot \frac{1}{2} sin (t)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2} sin (t)

约分:

2

= sin (t) \cdot 1

乘以:

sin (t) \cdot 1 = sin (t)

= sin (t)

化简

2 (- \frac{1}{2}) : - 1

2 (- \frac{1}{2})

去除括号:

(- a) = - a

= - 2 \cdot \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 2}{2}

约分:

2

= - 1

sin (t) = - 1

sin (t) = - 1

sin (t) = - 1

sin (t) = - 1

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

t = \frac{3 π}{2} + 2 πn

t = \frac{3 π}{2} + 2 πn

作图

流行的例子

20sin^2(x)-21sin(x)+4=0

20 sin^{2} (x) - 21 sin (x) + 4 = 0

4 tan (x) + 1 = 0

cot^2(θ)=-cot(θ)

cot^{2} (θ) = - cot (θ)

0.2727=sec(2.746x)-1

0.2727 = sec (2.746 x) - 1

2sqrt(3)sin(2θ)=sqrt(3),0<= θ<2pi

23 sin (2 θ) = 3, 0 \leq θ < 2 π