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受欢迎的三角函数 >

sqrt(2)csc(θ)-2=0

解答

2 csc (θ) - 2 = 0

解答

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

+1

度数

θ = 4 5^{\circ} + 36 0^{\circ} n, θ = 13 5^{\circ} + 36 0^{\circ} n

求解步骤

2 csc (θ) - 2 = 0

将

2

到右边

2 csc (θ) - 2 = 0

两边加上

2

2 csc (θ) - 2 + 2 = 0 + 2

化简

2 csc (θ) = 2

2 csc (θ) = 2

两边除以

2

2 csc (θ) = 2

两边除以

2

\frac{2 csc ( θ )}{2} = \frac{2}{2}

化简

\frac{2 csc ( θ )}{2} = \frac{2}{2}

化简

\frac{2 csc ( θ )}{2} : csc (θ)

\frac{2 csc ( θ )}{2}

约分:

2

= csc (θ)

化简

\frac{2}{2} : 2

\frac{2}{2}

使用根式运算法则:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{2}{2 ^{\frac{1}{2}}}

使用指数法则:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{1}}{2 ^{\frac{1}{2}}} = 2^{1 - \frac{1}{2}}

= 2^{1 - \frac{1}{2}}

数字相减:

1 - \frac{1}{2} = \frac{1}{2}

= 2^{\frac{1}{2}}

使用根式运算法则:

a^{\frac{1}{n}} = n a

2^{\frac{1}{2}} = 2

= 2

csc (θ) = 2

csc (θ) = 2

csc (θ) = 2

csc (θ) = 2

的通解

csc (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

作图

流行的例子

sin(θ)=(sqrt(5))/4

sin (θ) = \frac{5}{4}

100=50sqrt(40)cos(θ)

100 = 5040 cos (θ)

cos (3 x) = \frac{2}{3}

4cos^3(x)-7cos(x)-3=0

4 cos^{3} (x) - 7 cos (x) - 3 = 0

(sin(θ))/(1.3)=(sin(125))/(2.8519)

\frac{sin ( θ )}{1.3} = \frac{sin ( 12 5 ^{\circ} )}{2.8519}