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受欢迎的三角函数 >

sin(x)=(-sqrt(3))/2 ,270<x<360

解答

sin (x) = \frac{- 3}{2}, 27 0^{\circ} < x < 36 0^{\circ}

解答

x = 30 0^{\circ}

+1

弧度

x = \frac{5 π}{3}

求解步骤

sin (x) = \frac{- 3}{2}, 27 0^{\circ} < x < 36 0^{\circ}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

sin (x) = - \frac{3}{2}

sin (x) = - \frac{3}{2}

的通解

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 24 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

x = 24 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

在

27 0^{\circ} < x < 36 0^{\circ}

范围内的解

x = 30 0^{\circ}

作图

流行的例子

solvefor x,R=(v^2sin(2x))/g

so l v e f or x, R = \frac{v ^{2} sin ( 2 x )}{g}

sin(θ)csc(3θ-40)=1,calculetan(3θ)

sin (θ) csc (3 θ - 40) = 1, c a l c u l e tan (3 θ)

cos^2(x)+5cos(x)-6=0

cos^{2} (x) + 5 cos (x) - 6 = 0

solvefor x,sin(x)=-7/25

so l v e f or x, sin (x) = - \frac{7}{25}

1/(tan(α))+tan(α)= 1/(sin(α))

\frac{1}{tan ( α )} + tan (α) = \frac{1}{sin ( α )}