解答
sin2(2x)=2sin2(x)
解答
x=2πn,x=π+2πn,x=43π+2πn,x=45π+2πn,x=4π+2πn,x=47π+2πn
+1
度数
x=0∘+360∘n,x=180∘+360∘n,x=135∘+360∘n,x=225∘+360∘n,x=45∘+360∘n,x=315∘+360∘n求解步骤
sin2(2x)=2sin2(x)
两边减去 2sin2(x)sin2(2x)−2sin2(x)=0
分解 sin2(2x)−2sin2(x):(sin(2x)+2sin(x))(sin(2x)−2sin(x))
sin2(2x)−2sin2(x)
将 sin2(2x)−2sin2(x) 改写为 sin2(2x)−(2sin(x))2
sin2(2x)−2sin2(x)
使用根式运算法则: a=(a)22=(2)2=sin2(2x)−(2)2sin2(x)
使用指数法则: ambm=(ab)m(2)2sin2(x)=(2sin(x))2=sin2(2x)−(2sin(x))2
=sin2(2x)−(2sin(x))2
使用平方差公式: x2−y2=(x+y)(x−y)sin2(2x)−(2sin(x))2=(sin(2x)+2sin(x))(sin(2x)−2sin(x))=(sin(2x)+2sin(x))(sin(2x)−2sin(x))
(sin(2x)+2sin(x))(sin(2x)−2sin(x))=0
分别求解每个部分sin(2x)+2sin(x)=0orsin(2x)−2sin(x)=0
sin(2x)+2sin(x)=0:x=2πn,x=π+2πn,x=43π+2πn,x=45π+2πn
sin(2x)+2sin(x)=0
使用三角恒等式改写
sin(2x)+sin(x)2
使用倍角公式: sin(2x)=2sin(x)cos(x)=2sin(x)cos(x)+2sin(x)
sin(x)2+2cos(x)sin(x)=0
分解 sin(x)2+2cos(x)sin(x):sin(x)(2+2cos(x))
sin(x)2+2cos(x)sin(x)
因式分解出通项 sin(x)=sin(x)(2+2cos(x))
sin(x)(2+2cos(x))=0
分别求解每个部分sin(x)=0or2+2cos(x)=0
sin(x)=0:x=2πn,x=π+2πn
sin(x)=0
sin(x)=0的通解
sin(x) 周期表(周期为 2πn"):
x06π4π3π2π32π43π65πsin(x)02122231232221xπ67π45π34π23π35π47π611πsin(x)0−21−22−23−1−23−22−21
x=0+2πn,x=π+2πn
x=0+2πn,x=π+2πn
解 x=0+2πn:x=2πn
x=0+2πn
0+2πn=2πnx=2πn
x=2πn,x=π+2πn
2+2cos(x)=0:x=43π+2πn,x=45π+2πn
2+2cos(x)=0
将 2到右边
2+2cos(x)=0
两边减去 22+2cos(x)−2=0−2
化简2cos(x)=−2
2cos(x)=−2
两边除以 2
2cos(x)=−2
两边除以 222cos(x)=2−2
化简cos(x)=−22
cos(x)=−22
cos(x)=−22的通解
cos(x) 周期表(周期为 2πn):
x06π4π3π2π32π43π65πcos(x)12322210−21−22−23xπ67π45π34π23π35π47π611πcos(x)−1−23−22−210212223
x=43π+2πn,x=45π+2πn
x=43π+2πn,x=45π+2πn
合并所有解x=2πn,x=π+2πn,x=43π+2πn,x=45π+2πn
sin(2x)−2sin(x)=0:x=2πn,x=π+2πn,x=4π+2πn,x=47π+2πn
sin(2x)−2sin(x)=0
使用三角恒等式改写
sin(2x)−sin(x)2
使用倍角公式: sin(2x)=2sin(x)cos(x)=2sin(x)cos(x)−2sin(x)
−sin(x)2+2cos(x)sin(x)=0
分解 −sin(x)2+2cos(x)sin(x):sin(x)(−2+2cos(x))
−sin(x)2+2cos(x)sin(x)
因式分解出通项 sin(x)=sin(x)(−2+2cos(x))
sin(x)(−2+2cos(x))=0
分别求解每个部分sin(x)=0or−2+2cos(x)=0
sin(x)=0:x=2πn,x=π+2πn
sin(x)=0
sin(x)=0的通解
sin(x) 周期表(周期为 2πn"):
x06π4π3π2π32π43π65πsin(x)02122231232221xπ67π45π34π23π35π47π611πsin(x)0−21−22−23−1−23−22−21
x=0+2πn,x=π+2πn
x=0+2πn,x=π+2πn
解 x=0+2πn:x=2πn
x=0+2πn
0+2πn=2πnx=2πn
x=2πn,x=π+2πn
−2+2cos(x)=0:x=4π+2πn,x=47π+2πn
−2+2cos(x)=0
将 2到右边
−2+2cos(x)=0
两边加上 2−2+2cos(x)+2=0+2
化简2cos(x)=2
2cos(x)=2
两边除以 2
2cos(x)=2
两边除以 222cos(x)=22
化简cos(x)=22
cos(x)=22
cos(x)=22的通解
cos(x) 周期表(周期为 2πn):
x06π4π3π2π32π43π65πcos(x)12322210−21−22−23xπ67π45π34π23π35π47π611πcos(x)−1−23−22−210212223
x=4π+2πn,x=47π+2πn
x=4π+2πn,x=47π+2πn
合并所有解x=2πn,x=π+2πn,x=4π+2πn,x=47π+2πn
合并所有解x=2πn,x=π+2πn,x=43π+2πn,x=45π+2πn,x=4π+2πn,x=47π+2πn