arccos(x)= 5/6

Lösung

arccos (x) = \frac{5}{6}

x = cos (\frac{5}{6})

Schritte zur Lösung

arccos (x) = \frac{5}{6}

Wende die Eigenschaften der Trigonometrie an

arccos (x) = \frac{5}{6}

arccos (x) = a \Rightarrow x = cos (a)

x = cos (\frac{5}{6})

x = cos (\frac{5}{6})

5 cos (x) = - 2 sin^{2} (x) + 4, 0 \leq x \leq 2 π

4^{\frac{1}{3}} sec (x) = 4 (\frac{1}{4 ^{\frac{1}{3}}}) csc (x)

\frac{1 + tan ^{2} ( x )}{1 + tan ^{2} ( x )} = 1 - sin^{2} (x)

so l v e f or θ, tan (θ) = \frac{2 3}{2}

\frac{- 3 + 4 cos ^{2} ( θ )}{1 - 2 sin ( θ )} = a + b sin (θ)