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受欢迎的三角函数 >

sin^2(x)=((9m-9))/7

解答

sin^{2} (x) = \frac{( 9 m - 9 )}{7}

解答

x = arcsin (\frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (- \frac{9 m - 9}{7}) + 2 πn, x = arcsin (- \frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (\frac{9 m - 9}{7}) + 2 πn

求解步骤

sin^{2} (x) = \frac{( 9 m - 9 )}{7}

用替代法求解

sin^{2} (x) = \frac{9 m - 9}{7}

令

: sin (x) = u

u^{2} = \frac{9 m - 9}{7}

u^{2} = \frac{9 m - 9}{7} : u = \frac{9 m - 9}{7}, u = - \frac{9 m - 9}{7}

u^{2} = \frac{9 m - 9}{7}

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

u = \frac{9 m - 9}{7}, u = - \frac{9 m - 9}{7}

u = sin (x)

代回

sin (x) = \frac{9 m - 9}{7}, sin (x) = - \frac{9 m - 9}{7}

sin (x) = \frac{9 m - 9}{7}, sin (x) = - \frac{9 m - 9}{7}

sin (x) = \frac{9 m - 9}{7} : x = arcsin (\frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (- \frac{9 m - 9}{7}) + 2 πn

sin (x) = \frac{9 m - 9}{7}

使用反三角函数性质

sin (x) = \frac{9 m - 9}{7}

sin (x) = \frac{9 m - 9}{7}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (\frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (- \frac{9 m - 9}{7}) + 2 πn

x = arcsin (\frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (- \frac{9 m - 9}{7}) + 2 πn

sin (x) = - \frac{9 m - 9}{7} : x = arcsin (- \frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (\frac{9 m - 9}{7}) + 2 πn

sin (x) = - \frac{9 m - 9}{7}

使用反三角函数性质

sin (x) = - \frac{9 m - 9}{7}

sin (x) = - \frac{9 m - 9}{7}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- \frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (\frac{9 m - 9}{7}) + 2 πn

x = arcsin (- \frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (\frac{9 m - 9}{7}) + 2 πn

合并所有解

x = arcsin (\frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (- \frac{9 m - 9}{7}) + 2 πn, x = arcsin (- \frac{9 m - 9}{7}) + 2 πn, x = π + arcsin (\frac{9 m - 9}{7}) + 2 πn

作图

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