209cos(47)=150cos(θ)

Lösung

209 cos (4 7^{\circ}) = 150 cos (θ)

θ = 0.31675 \dots + 36 0^{\circ} n, θ = 36 0^{\circ} - 0.31675 \dots + 36 0^{\circ} n

Radianten

θ = 0.31675 \dots + 2 πn, θ = 2 π - 0.31675 \dots + 2 πn

Schritte zur Lösung

209 cos (4 7^{\circ}) = 150 cos (θ)

Tausche die Seiten

150 cos (θ) = 209 cos (4 7^{\circ})

Teile beide Seiten durch

150

150 cos (θ) = 209 cos (4 7^{\circ})

Teile beide Seiten durch

150

\frac{150 cos ( θ )}{150} = \frac{209 cos ( 4 7 ^{\circ} )}{150}

Vereinfache

cos (θ) = \frac{209 cos ( 4 7 ^{\circ} )}{150}

cos (θ) = \frac{209 cos ( 4 7 ^{\circ} )}{150}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{209 cos ( 4 7 ^{\circ} )}{150}

Allgemeine Lösung für

cos (θ) = \frac{209 cos ( 4 7 ^{\circ} )}{150}

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

θ = arccos (\frac{209 cos ( 4 7 ^{\circ} )}{150}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{209 cos ( 4 7 ^{\circ} )}{150}) + 36 0^{\circ} n

θ = arccos (\frac{209 cos ( 4 7 ^{\circ} )}{150}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{209 cos ( 4 7 ^{\circ} )}{150}) + 36 0^{\circ} n

Zeige Lösungen in Dezimalform

θ = 0.31675 \dots + 36 0^{\circ} n, θ = 36 0^{\circ} - 0.31675 \dots + 36 0^{\circ} n

7 - 5 cos (x) = 10, 7 - 5 cos (x) = 10

cos (4 x) = cos (x)

- 4 cos (2 θ) - 19 = - 26 cos (θ), 0 \leq θ < 36 0^{\circ}

3 cos^{2} (x) = 7 - 8 sin (x)

sin (X) = - \frac{1}{2}