9^{-x}=3^{x+2}

Lösung

9^{- x} = 3^{x + 2}

x = - \frac{2}{3}

Dezimale

x = - 0.66666 \dots

Schritte zur Lösung

9^{- x} = 3^{x + 2}

Wende Exponentenregel an

- 2 x = x + 2

Löse

- 2 x = x + 2 : x = - \frac{2}{3}

x = - \frac{2}{3}

7^{2 x + 3} = 7^{3 x - 4}

so l v e f or x, x^{y} = e^{x - y}

1 0^{2 x + 6} = 243

e^{x + 1} = 1

2 7^{2 x - 1} = 9^{x - 2}