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Beliebt Algebra >

2x^3-7x^2+4x+1=0

Lösung

2 x^{3} - 7 x^{2} + 4 x + 1 = 0

Lösung

x = 1, x = \frac{5 + 33}{4}, x = \frac{5 - 33}{4}

+1

Dezimale

x = 1, x = 2.68614 \dots, x = - 0.18614 \dots

Schritte zur Lösung

2 x^{3} - 7 x^{2} + 4 x + 1 = 0

Faktorisiere

2 x^{3} - 7 x^{2} + 4 x + 1 : (x - 1) (2 x^{2} - 5 x - 1)

(x - 1) (2 x^{2} - 5 x - 1) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x - 1 = 0 or 2 x^{2} - 5 x - 1 = 0

Löse

x - 1 = 0 : x = 1

Löse

2 x^{2} - 5 x - 1 = 0 : x = \frac{5 + 33}{4}, x = \frac{5 - 33}{4}

Die Lösungen sind

x = 1, x = \frac{5 + 33}{4}, x = \frac{5 - 33}{4}

Graph

Beliebte Beispiele

2t^3-3t^2-2t-42=0

2 t^{3} - 3 t^{2} - 2 t - 42 = 0

x^3+3x^2-2x-2=0

x^{3} + 3 x^{2} - 2 x - 2 = 0

-x^3+10x^2-33x+36=0

- x^{3} + 10 x^{2} - 33 x + 36 = 0

x^{3} - 6 x = 3 x^{2} - 8

y^{4} - 4 y = 0