integral of 2zsin(2z)-cos(2z)

Lösung

\int 2 z sin (2 z) - cos (2 z) d z

- z cos (2 z) + C

Schritte zur Lösung

\int 2 z sin (2 z) - cos (2 z) d z

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 z sin (2 z) d z - \int cos (2 z) d z

\int 2 z sin (2 z) d z = - z cos (2 z) + \frac{1}{2} sin (2 z)

\int cos (2 z) d z = \frac{1}{2} sin (2 z)

= - z cos (2 z) + \frac{1}{2} sin (2 z) - \frac{1}{2} sin (2 z)

Addiere gleiche Elemente:

\frac{1}{2} sin (2 z) - \frac{1}{2} sin (2 z) = 0

= - z cos (2 z)

Füge eine Konstante zur Lösung hinzu

= - z cos (2 z) + C

\int cos (x) \cdot cos (n x) d x

\int \frac{x ^{2} + 1}{x - 2} d x

\int e^{- x^{3}} x^{2} d x

\int 3^{2 x + 1} d x

\int \frac{x ^{4}}{4 x} d x