integral x(2x+1)^3

Lösung

integral

x (2 x + 1)^{3}

\frac{8 x ^{5}}{5} + 3 x^{4} + 2 x^{3} + \frac{x ^{2}}{2} + C

Schritte zur Lösung

\int x (2 x + 1)^{3} d x

Multipliziere aus

x (2 x + 1)^{3} : 8 x^{4} + 12 x^{3} + 6 x^{2} + x

= \int 8 x^{4} + 12 x^{3} + 6 x^{2} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{4} d x + \int 12 x^{3} d x + \int 6 x^{2} d x + \int x d x

\int 8 x^{4} d x = \frac{8 x ^{5}}{5}

\int 12 x^{3} d x = 3 x^{4}

\int 6 x^{2} d x = 2 x^{3}

\int x d x = \frac{x ^{2}}{2}

= \frac{8 x ^{5}}{5} + 3 x^{4} + 2 x^{3} + \frac{x ^{2}}{2}

Füge eine Konstante zur Lösung hinzu

= \frac{8 x ^{5}}{5} + 3 x^{4} + 2 x^{3} + \frac{x ^{2}}{2} + C

in t e g r a l x (x + 2)^{\frac{1}{2}}

in t e g r a l \frac{1}{( y ^{2} - y )}

in t e g r a l \frac{1}{a - x}

in t e g r a l (e^{x})^{- 1}

in t e g r a l \frac{1}{x ( x + 1 )}