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受欢迎的三角函数 >

1-sin(θ)= 1/2

解答

1 - sin (θ) = \frac{1}{2}

解答

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

+1

度数

θ = 3 0^{\circ} + 36 0^{\circ} n, θ = 15 0^{\circ} + 36 0^{\circ} n

求解步骤

1 - sin (θ) = \frac{1}{2}

将

1

到右边

1 - sin (θ) = \frac{1}{2}

两边减去

1

1 - sin (θ) - 1 = \frac{1}{2} - 1

化简

1 - sin (θ) - 1 = \frac{1}{2} - 1

化简

1 - sin (θ) - 1 : - sin (θ)

1 - sin (θ) - 1

同类项相加:

1 - 1 = 0

= - sin (θ)

化简

\frac{1}{2} - 1 : - \frac{1}{2}

\frac{1}{2} - 1

将项转换为分式:

1 = \frac{1 \cdot 2}{2}

= - \frac{1 \cdot 2}{2} + \frac{1}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 2 + 1}{2}

- 1 \cdot 2 + 1 = - 1

- 1 \cdot 2 + 1

数字相乘:

1 \cdot 2 = 2

= - 2 + 1

数字相加/相减:

- 2 + 1 = - 1

= - 1

= \frac{- 1}{2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

- sin (θ) = - \frac{1}{2}

- sin (θ) = - \frac{1}{2}

- sin (θ) = - \frac{1}{2}

两边除以

- 1

- sin (θ) = - \frac{1}{2}

两边除以

- 1

\frac{- sin ( θ )}{- 1} = \frac{- \frac{1}{2}}{- 1}

化简

\frac{- sin ( θ )}{- 1} = \frac{- \frac{1}{2}}{- 1}

化简

\frac{- sin ( θ )}{- 1} : sin (θ)

\frac{- sin ( θ )}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{sin ( θ )}{1}

使用法则

\frac{a}{1} = a

= sin (θ)

化简

\frac{- \frac{1}{2}}{- 1} : \frac{1}{2}

\frac{- \frac{1}{2}}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{\frac{1}{2}}{1}

使用分式法则:

\frac{a}{1} = a

= \frac{1}{2}

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2}

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

作图

流行的例子

3sqrt(3)tan(x)=3

33 tan (x) = 3

0 = sin (3 x)

3sin(x)cos(x)=2cos(x)

3 sin (x) cos (x) = 2 cos (x)

sin(2x+pi/3)=(sqrt(3))/2

sin (2 x + \frac{π}{3}) = \frac{3}{2}

6 sin (20 x) + 1 = 1