cos(θ)= 9/17

Lösung

cos (θ) = \frac{9}{17}

θ = 1.01288 \dots + 2 πn, θ = 2 π - 1.01288 \dots + 2 πn

Grad

θ = 58.03428 \dots^{\circ} + 36 0^{\circ} n, θ = 301.96571 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{9}{17}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{9}{17}

Allgemeine Lösung für

cos (θ) = \frac{9}{17}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{9}{17}) + 2 πn, θ = 2 π - arccos (\frac{9}{17}) + 2 πn

θ = arccos (\frac{9}{17}) + 2 πn, θ = 2 π - arccos (\frac{9}{17}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 1.01288 \dots + 2 πn, θ = 2 π - 1.01288 \dots + 2 πn

- 1 = \frac{tan ( x ) - ( \frac{3}{4} )}{1 + tan ( x ) ( \frac{3}{4} )}

cos (x) = - \frac{15}{13}

arctan (\frac{20}{x}) - arctan (\frac{400}{x}) = - 9.72

cos (θ) = \frac{9}{15}

tan (t) = - \frac{5}{12}